AMC 10 Step by Step

2009 AMC 10A

All 25 problems, 75 minutes, scored 6 / 1.5 / 0. The answer key and the idea behind each problem are on this page too, folded away until you ask for them.

The problems

Show the answer key, topics and key insights

This gives away all 25 answers and the idea behind each one. Sit the paper first if you mean to.

#AnswerTopicDifficultyKey insight
1ELinear Equations & Word ProblemsDivide 128 by 12 and round up, because a partially used can still counts as a whole can.
2ANumber PropertiesA total ending in 5 forces the number of pennies to be a multiple of 5, hence zero; then four coins of at least 5 cents total at least 20.
3CFractions & DecimalsSimplify from the innermost fraction outward: 1 + 1/2 = 3/2, its reciprocal is 2/3, and 1 + 2/3 = 5/3.
4ALinear Equations & Word ProblemsBudget time, not speed: the swim takes 1/8 hour and the run 1/2 hour, leaving 11/8 hour for the 15-mile ride.
5EBases & DigitsRepunit squares form a palindrome that climbs 1, 2, ..., 9 and back down, so the digits sum to 2(1+...+8)+9 = 81.
6ACirclesThe inscribed circle's diameter equals the semicircle's radius, so the semicircle has radius 4 and area 8 pi, exactly twice the circle's 4 pi.
7CRatios, Percents & AveragesForty percent less than the whole-milk fat means 2 is 60% of it, so the whole-milk percentage is 2 divided by 0.6.
8BRatios, Percents & AveragesA senior ticket is 75% of full price, so full price is 6 / 0.75 = 8; then the six tickets cost 2(8) + 2(6) + 2(4).
9BSequences & SeriesThe third term a r^2 = 2009 = 7^2 * 41 and r > 1 is an integer, so r^2 | 2009 forces r = 7 and a = 41.
10BSimilar & Congruent TrianglesThe altitude to the hypotenuse is the geometric mean of the pieces it cuts: BD^2 = 3 * 4, so BD = 2 sqrt 3 and the area is (1/2)(7)(BD).
11DAlgebraic ManipulationThe new box is s(s+1)(s-1) = s^3 - s by difference of squares, so the volume drops by exactly s; a drop of 5 means s = 5.
12CTriangles: Area & PythagoreanTriangle BCD forces BD > 17 - 5 = 12 and triangle ABD forces BD < 5 + 9 = 14, so the integer BD is 13.
13EExponents, Logarithms & RadicalsWrite 12^(mn) = 2^(2mn) 3^(mn) and re-group each prime power as a power of P or Q: 2^(2mn) = P^(2n), 3^(mn) = Q^m.
14AQuadrilaterals & Polygon AreasThe outer square has side a + b and the inner square side a - b, so an area ratio of 4 means a + b = 2(a - b).
15ESequences & SeriesEach new outer square adds 4(n-1) diamonds, so F_n = 1 + 4(1 + 2 + ... + (n-1)) = 2n(n-1) + 1, and F_20 = 761.
16DAbsolute Value & InequalitiesTelescope a - d = (a-b) + (b-c) + (c-d) = ±2 ± 3 ± 4; the eight sign choices give |a-d| in {1, 3, 5, 9}, summing to 18.
17CSimilar & Congruent TrianglesEF is the hypotenuse of right triangle DEF with altitude DB = 5; triangles DBE and DBF are scaled copies of the 3-4-5 triangles DAB and DCB.
18DRatios, Percents & AveragesTake 100 children: 60 play soccer, 24 of them swim, so 36 soccer players don't swim, out of 70 non-swimmers: 36/70 = 51%.
19BDivisibility & FactorsRolling without slipping, the same point of B touches again only if r divides 100; 100 has 9 divisors, and r < 100 removes one.
20DLinear Equations & Word ProblemsThe 1 km/min closing rate splits 3:1, so Lauren rides 1/4 km/min; after 5 minutes 15 km remain and Lauren alone needs 60 more minutes.
21CCirclesThe four small centers form a square of side 2r, so each is r sqrt 2 from the big center and the big radius is r(1 + sqrt 2).
22DBasic ProbabilityBy symmetry the two top numbers are a uniformly random pair of distinct labels from the bag; given the first, exactly 2 of the remaining 11 labels complete a 7.
23ESimilar & Congruent TrianglesEqual areas of AED and BEC force AB parallel to CD, so triangles AEB and CED are similar with ratio 9 : 12, and AE = (3/7)(14).
24CBasic ProbabilityA plane through three vertices misses the interior only when all three lie on one face; 6 faces times C(4,3) = 24 bad triples out of C(8,3) = 56.
25BDivisibility & FactorsI_k = 2^(k+2) 5^(k+2) + 2^6; factor out the smaller power of 2, and only the tie k = 4 gives an extra factor from 5^6 + 1.

Problems © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. The topic tags, difficulty ratings and key insights on this page are original to this site. No problem statements are reproduced here — each links to its own page.