AMC 10 Step by Step
2009 AMC 10AProblem 17P16-20~6 minPrint

Rectangle ABCDABCD has AB=4AB=4 and BC=3BC=3 . Segment EFEF is constructed through BB so that EFEF is perpendicular to DBDB , and AA and CC lie on DEDE and DFDF , respectively. What is EFEF ?

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.