Ratios, Percents & Averages
Ratio, proportion, percent change, means/averages as arithmetic word problems
Ratios, Percents & AveragesAMC 10 Step by Step
Name: Date: October 28, 2026
Algebra · 79 problems have this as their main idea
79
primary-topic problems (6.1% of all)
58
more as a secondary topic
Where it appears
63
P1-10
12
P11-15
3
P16-20
1
P21-25
What you need to know
- A ratio means "the same number of parts." If , then , , and for one number (the size of one part). Work with and instead of fractions. Example: boys to girls is in a class of . Then , so : boys and girls.
- Percent changes multiply. A increase multiplies by , and a decrease multiplies by . Several changes in a row multiply together. Example: up and then down is , so you end lower.
- A percent is always a percent "of" something, and that something is the base. Example: is more than (base ), but is less than (base ).
- Mean count sum. Example: tests averaging add up to .
- A combined average is a weighted average. Add the sums and divide by the total count. The result is closer to the mean of the larger group. Example: students average and students average . All average , which is closer to .
- Chaining ratios. If and , scale both so matches. Multiply the first by and the second by : and , so .
How AMC 10 tests it
- Problems 1–6: one percent or ratio computation (a markup followed by a discount, or the ratio of areas after scaling a side).
- Problems 4–10: "the average of numbers is ; after one number is removed or added, the average becomes ..." Change the averages into sums.
- Problems 6–12: chained ratios among three or more groups, leading to a small linear equation.
- Problems 8–14: percents where the base is unknown, such as "what percent increase brings the price back to the original?"
Standard approaches
- Pick a handy total: for percents, the LCM of the ratio parts, or parts , , … with unknown.
- Change every average into a sum right away.
- Write each percent change as a multiplier and multiply them. Change back to a percent only at the end.
- For "what percent" answers, decide carefully what the base is: the original amount, the new amount, or the other quantity. Example: after a discount, a increase brings the price back, since .
- Check that the answer goes the right way: a discount lowers the price, and a combined average lies between the group averages.
Worked example
In a club the ratio of freshmen to sophomores is . After freshmen join and sophomores leave, the ratio becomes . How many members did the club have originally?
(A) (B) (C) (D) (E)
Say there were freshmen and sophomores at first. Afterward there are freshmen and sophomores, and their ratio is :
Cross-multiply: , so .
Move the terms to one side: , so and .
The question asks for the whole club, which is members.
Check: freshmen and sophomores become and , and . The answer is .
Pitfalls
- Taking a percent of the wrong base. A discount and then a increase does not bring you back: becomes and then .
- Adding percents that have different bases. Up and then up is , a increase, not .
- Averaging group averages without weighting by group size. In the example above, is wrong; the true average is .
- Giving one part when the whole is asked, or the whole when one part is asked. A ratio of means parts in all: in the worked example, is only the freshmen.
Traps that recur
- Approximating each cost against the whole allowance (20% + 5% = 25%) instead of against the stated differences. (2017 AMC 10A #14)
- Taking 40% of the 30 swimmers instead of 40% of the 60 soccer players, or dividing the 36 by 100 rather than by the 70 non-swimmers. (2009 AMC 10A #18)
- Finding n = 4 coins and 80 cents but then guessing a coin mix (like 25 + 25 + 10 + 10 + 10) without checking it uses exactly four coins. (2004 AMC 10A #14)
- Pouring half of the second cup's original 4 ounces (2 oz) back instead of half of its new 6 ounces (3 oz, in a 1:2 coffee-to-cream ratio). (2002 AMC 10A #17)
Problems, easiest first
Open any of them to try it here; the worked solution is on the problem's own page.
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