2009 AMC 10A Problem 8
Three generations of the Wen family are going to the movies, two from each generation. The two members of the youngest generation receive a % discount as children. The two members of the oldest generation receive a discount as senior citizens. The two members of the middle generation receive no discount. Grandfather Wen, whose senior ticket costs , is paying for everyone. How many dollars must he pay?
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Key insight
A senior ticket is 75% of the full price, so the full price is 6 divided by 0.75, which is 8 dollars; a child ticket is half of that.
Solution
All three kinds of ticket are based on the same full price, so find the full price first.
1. A senior gets off, so a senior pays of the full price. That is :
2. A child gets off, so a child ticket costs half of , which is dollars.
3. Add up two tickets of each kind:
| Generation | Price each | Two tickets |
|---|---|---|
| Middle (full price) | ||
| Oldest (senior) | ||
| Youngest (child) |
- Total: dollars.
The answer is .
Why this works
When every price is a fixed part of one unknown price, find that unknown first. To undo a discount, divide by the part that is left (); adding the back on to gives , because of is smaller than of .
Concise solution
A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.
A senior ticket is the full price with removed, i.e. of full price. Since that equals , the full price is
Now price each generation:
- Middle generation (no discount): .
- Oldest generation (seniors): .
- Youngest generation (half price): .
Total: dollars.
The answer is .
Review in the AoPS books
- Introduction to Algebra, Chapter 6: Ratios and Percents
- Introduction to Algebra, Chapter 7: Proportion (§7.1, §7.2, §7.3)
- Prealgebra, Chapter 13: Data and Statistics (§13.1)
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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.