AMC 10 Step by Step

2009 AMC 10A Problem 3

P1-10~1 minPrint

Which of the following is equal to 1+11+11+11 + \frac{1}{1+\frac{1}{1+1}} ?

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Key insight

Work from the innermost part outward: 1 + 1 = 2, then 1 + 1/2 = 3/2, flip it to get 2/3, then 1 + 2/3 = 5/3.

Solution

A fraction stacked inside a fraction is easiest to handle from the inside out, one layer at a time.

  1. The deepest part is 1+1=21 + 1 = 2.
  2. The next layer is 1+12=321 + \frac{1}{2} = \frac{3}{2}.
  3. Now we need 13/2\dfrac{1}{3/2}. Dividing 11 by a fraction flips it, so this is 23\frac{2}{3}.
  4. The outer layer is 1+23=531 + \frac{2}{3} = \frac{5}{3}.

The answer is (C) 53\boxed{\textbf{(C)}\ \frac{5}{3}}.

Why this works

Each layer of this stacked fraction is "one plus one over the layer below it." Doing one layer at a time and writing each result as a single fraction keeps you from mixing up which number goes on top.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Work from the inside out.

The innermost piece is 1+1=21 + 1 = 2, so the middle denominator is
1+12=32.1 + \frac{1}{2} = \frac{3}{2}.
Its reciprocal is 23\frac{2}{3}, so the whole expression is
1+23=53.1 + \frac{2}{3} = \frac{5}{3}.

The answer is (C) 53\boxed{\textbf{(C)}\ \frac{5}{3}}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.