AMC 10 Step by Step

2003 AMC 10A

All 25 problems, 75 minutes, scored 6 / 1.5 / 0. The answer key and the idea behind each problem are on this page too, folded away until you ask for them.

The problems

Show the answer key, topics and key insights

This gives away all 25 answers and the idea behind each one. Sit the paper first if you mean to.

#AnswerTopicDifficultyKey insight
1DSequences & SeriesPair the k-th even number 2k with the k-th odd number 2k-1; every pair differs by exactly 1, and there are 2003 pairs.
2BLinear Equations & Word ProblemsEach member's kit costs 2(4 + 9) = 26 dollars, so the head count is 2366 divided by 26.
3DSolid GeometryA box has 8 corners, so 8 cubes of volume 27 are removed from a box of volume 1200.
4ALinear Equations & Word ProblemsAverage speed is total distance over total time: 2 km in 40 minutes, which is 3 km/hr.
5BQuadraticsThe coefficients 2 + 3 - 5 sum to zero, so x = 1 is a root and the factor (root - 1) kills the product.
6CAbsolute Value & Inequalitiesx heart 0 is |x|, which equals x only for nonnegative x; a single negative test value like x = -3 breaks statement (C).
7BTriangles: Area & PythagoreanThe longest side must be less than half the perimeter, so it is 3; the other two sides sum to 4, giving only (3,3,1) and (3,2,2).
8EDivisibility & Factors60 = 2^2 * 3 * 5 has 12 divisors, and every integer from 1 to 6 divides 60, so 6 of the 12 qualify.
9AExponents, Logarithms & RadicalsThe innermost cube root of x*sqrt(x) = x^{3/2} is exactly sqrt(x), so each layer reproduces sqrt(x) and the whole tower collapses.
10ESolid GeometryFold the four given squares first; they form a bottom and three walls, and a new square works exactly when it folds onto one of the two missing faces.
11EBases & DigitsBoth numbers are 100 times the three-digit number AMC plus 10 or 12, so 200*AMC + 22 = 123422 and AMC = 617.
12AGeometric ProbabilityInside the 4-by-1 rectangle, x < y only in the small triangle above the line y = x, which has area 1/2 out of 4.
13ASystems of EquationsThe first number is 4 times the other two combined, so it is 4/5 of the total, namely 16; the remaining 4 splits 7:1.
14APrimesOnly e = 3 or 7 lets 10d + e be prime; the four survivors 23, 37, 53, 73 make 7 * 3 * 73 = 1533 the largest product.
15CDivisibility & FactorsCount the 50 even numbers, then remove the 16 multiples of 6; 34 of 100 remain.
16CModular ArithmeticPowers of 3 end in the cycle 3, 9, 7, 1; since 2003 leaves remainder 3 on division by 4, the units digit is the third entry, 7.
17BCirclesAn equilateral triangle inscribed in a circle of radius r has side r*sqrt(3), so 3*sqrt(3)*r = pi*r^2 and r = 3*sqrt(3)/pi.
18BQuadraticsSubstituting y = 1/x turns the equation into y^2 + y + 2003/2004 = 0, whose roots are the reciprocals; Vieta gives their sum as -1 at once.
19CCirclesThe lune is the small semicircle minus the big circle's segment cut by the small diameter, a chord subtending 60 degrees, so segment = pi/6 - sqrt(3)/4.
20EBases & DigitsThree digits in base b means b^2 <= n < b^3, so n must lie in [121, 728]; that is 608 of the 900 three-digit numbers, about 0.68.
21DDistributions & Stars and BarsAn assortment is a nonnegative solution of a + b + c = 6, and stars and bars counts these as C(8,2) = 28.
22BSimilar & Congruent TrianglesTriangles GCH and GEA are similar with ratio CH:EA = 3:5, and their altitudes from G differ by the rectangle's width 8, so GF = 20.
23CBasic CountingEvery toothpick is a side of exactly one upward-pointing small triangle, and there are 1 + 2 + ... + 1002 of those, so multiply that sum by 3.
24ELogic PuzzlesRed 5 divides only blue 5 and red 4 only blue 4, so those reds sit at the ends; the rest of the stack is forced card by card.
25BModular Arithmeticn = 100q + r = 99q + (q + r) and 11 divides 99, so 11 | q + r means 11 | n; count five-digit multiples of 11.

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