2003 AMC 10A Problem 2

First find the cost for one member, then see how many members fit into the total bill.

1. A pair of socks costs $4$ dollars. A T-shirt costs $5$ dollars more, so it costs $4 + 5 = 9$ dollars.
2. One set for home games is one pair of socks and one shirt: $4 + 9 = 13$ dollars.
3. Each member also needs a second set for away games, so one member spends $2 \times 13 = 26$ dollars.
4. The whole league spends $2366$ dollars, so the number of members is
$$2366 \div 26 = 91.$$
5. Check: $26 \times 91 = 26 \times 90 + 26 = 2340 + 26 = 2366$. Correct.

The answer is $\boxed{\textbf{(B)}\ 91}$.

Total cost = (cost for one member) $\times$ (number of members). Once the cost for one member is right, the rest is a single division. The only danger is the words: "another pair of socks and a shirt" doubles everything, so read every item before you add.