2005 AMC 10B
All 25 problems, 75 minutes, scored 6 / 1.5 / 0. The answer key and the idea behind each problem are on this page too, folded away until you ask for them.
The problems
Show the answer key, topics and key insights
This gives away all 25 answers and the idea behind each one. Sit the paper first if you mean to.
The same key as a PDF 126 KB — a separate file from the paper, so one can be handed over without the other.
| # | Answer | Topic | Difficulty | Key insight |
|---|---|---|---|---|
| 1 | A | Ratios, Percents & Averages | Find the price of one bar when buying (40 cents) and when selling (50 cents). Each bar earns 10 cents, and there are 1000 bars. | |
| 2 | D | Ratios, Percents & Averages | The phrase 'x percent of x' means x divided by 100, then times x. Setting that equal to 4 gives x times x = 400, so x = 20. | |
| 3 | D | Ratios, Percents & Averages | Using one third of the paint leaves two thirds. This happens twice, so what remains is two thirds of two thirds, which is 4/9. | |
| 4 | D | Functions | A negative number squared is positive, so both inner parts equal 13. Then 13 diamond 13 is 13 times the square root of 2. | |
| 5 | C | Ratios, Percents & Averages | If one third of the CDs costs one fifth of her money, then all the CDs cost three times as much: three fifths. Two fifths is left. | |
| 6 | B | Ratios, Percents & Averages | Her goal is 40 A's out of all 50 quizzes. She has 22, so she needs 18 of the last 20 quizzes to be A's. Only 2 can be lower. | |
| 7 | B | Circles | A circle in a square has diameter equal to the side; a square in a circle has diagonal equal to the diameter. Start with side 2. | |
| 8 | A | Circles | On one tile, the four white quarter circles fit together into one whole circle of radius 1/2. So each tile has 1 minus pi/4 shaded, and there are 80 tiles. | |
| 9 | D | Basic Probability | The sum is odd only when one die is odd and the other even. The first die is odd 2/3 of the time, the second only 1/3. | |
| 10 | A | Triangles: Area & Pythagorean | Drop a perpendicular from C; it lands at the middle of AB. Its length squared is 48, so its foot is 4 from D, and BD = 4 - 1. | |
| 11 | E | Sequences & Series | Write out terms until one repeats. From term 2 on, the sequence cycles 133, 55, 250 every 3 terms, and term 2005 lands on 250, like term 4. | |
| 12 | E | Basic Probability | A prime product needs eleven dice showing 1 and one die showing 2, 3 or 5: 12 times 3 = 36 good outcomes out of 6 to the 12th. | |
| 13 | C | Inclusion-Exclusion | Multiples of 12 appear in both the list of multiples of 3 and the list of multiples of 4. To remove them completely, subtract their count twice. | |
| 14 | C | Triangles: Area & Pythagorean | Use CD = 2 as the base. M is halfway up side AC, so its height above line BD is half the triangle's height, or half of root 3. | |
| 15 | D | Basic Probability | Only two kinds of pairs reach 20 dollars: any pair with a twenty, or the two tens. That is 14 of the 28 possible pairs. | |
| 16 | D | Quadratics | Doubling both roots doubles their sum and multiplies their product by 4. Comparing coefficients gives m = 2p and n = 4m, so n = 8p. | |
| 17 | B | Exponents, Logarithms & Radicals | Plug each equation into the next to get 8 = 4 raised to the power abcd. Since 8 is 2 cubed and 4 is 2 squared, abcd = 3/2. | |
| 18 | D | Basic Counting | Seven different digits in increasing order can be arranged only one way. So a phone number is fixed by which of the eight digits 2 through 9 is left out. | |
| 19 | B | Statistics & Data | Pretend there are 20 students. The total of all scores divided by 20 gives the mean, 86. The middle students score 85, the median. | |
| 20 | C | Basic Counting | Each of the five digits sits in each place equally often, so every place averages (1+3+5+7+8)/5 = 4.8. The average number is 4.8 times 11111. | |
| 21 | A | Basic Probability | Both probabilities have the same bottom, so q/p is just the count of two-pair draws (1620) divided by the count of four-of-a-kind draws (10). | |
| 22 | C | Divisibility & Factors | After simplifying, the question is whether n + 1 divides 2 times (n - 1) factorial. This fails only when n + 1 is an odd prime: 8 times. | |
| 23 | C | Quadrilaterals & Polygon Areas | EF joins the midpoints of the legs, so its length is the average of the two bases, and both smaller trapezoids have half the height. | |
| 24 | E | Diophantine Equations | With digits a and b, x squared minus y squared equals 99(a + b)(a - b). So a + b must be 11 and a - b a perfect square. | |
| 25 | C | Sets, Estimation & Miscellaneous | Numbers 1 to 24 have no partner making 125, so keep them all. Numbers 25 to 100 form 38 pairs; keep one from each: 62. |
2005 AMC 10B. Problems © Mathematical Association of America, American Mathematics Competitions (maa.org/amc), licensed CC BY-NC-SA 4.0. Typeset and annotated by AMC 10 Step by Step (amcstep.com) and shared under the same licence. Not endorsed by the MAA.