Statistics & Data
Mean, median, mode, range, data tables, charts, weighted averages
What you need to know
- Mean , so sum mean count. Almost every problem about a mean is really about the total. Example: five numbers with mean add up to .
- Median: put the numbers in order first. With an odd count, the median is the middle number. With an even count, it is the average of the two middle numbers. Example: sorts to , with median . And sorts to , with median .
- Mode: the value that appears most often. "Unique mode" means it appears strictly more often than every other value; a tie is not allowed. Example: has unique mode , but has no unique mode, since and tie.
- Range largest smallest. Example: has range .
- Combining two groups (a weighted average). If a group of people has mean and a group of people has mean , the mean of everyone is . Example: students averaging and averaging give .
How AMC 10 tests it
- Problems 1–8: find one statistic from another. The hard part is not mixing up the mean and the median.
- "After the next test my average will be ": change the averages into totals and subtract. Example: to go from an average of on tests to on , you need .
- Middle-of-the-paper problems where the mean, median, mode, and range are all given and you find the largest possible number in the list. Solve them with a bound plus a list that reaches it.
Standard approaches
- Rewrite every mean as a sum, and every median as a fact about a certain position in the sorted list.
- When numbers are added or removed, keep track of totals, not averages.
- For largest/smallest problems, first place the values that are forced (the median spot, the repeated mode). Then push the free values as far as they can go.
- Bound first, then build: show the larger answer is impossible, then write down a list that reaches the next one.
Worked example
A list of five positive integers has mean , median , and unique mode . What is the largest possible range of the list?
(A) (B) (C) (D) (E)
Solution. Write the list in order as .
Use the mean and median. The mean is , so the sum is . The median is the middle number, so .
Use the mode. The mode must appear at least twice. Only and can be , since , , are at most . So , and .
Make the range big. The range is , so we want as small as possible, which means as large as possible. Since appears exactly twice and is the unique mode, no other value may appear twice: and . As , this leaves , so .
Check that it works. The list has sum , median , and unique mode . Its range is . The answer is .
Pitfalls
- Giving the mean when the sum is asked, or the median when the mean is asked.
- Forgetting to sort before finding the median. Example: the middle of as written is , but the median is .
- Ignoring "unique" in "unique mode." Example: has sum and median , but ties with , so its range of is not allowed.
- Averaging group averages without weighting by group size. Example: above, is wrong; the true mean is .
Traps that recur
- Treating the median as 5.2 or one of the given numbers; with nine values the fifth must be an integer, so one of x, y, z has to sit in the middle. (2024 AMC 10B #15)
- Using five 8s to fill the bottom, which forces the other values up and yields 24; fewer 8s lets 1s in and gives a bigger maximum. (2014 AMC 10B #18)
- Ignoring that the mode must be unique, or forgetting the mean fixes the total at 64. (2002 AMC 10A #21)
- Assuming the mean is always the largest of the three statistics; when the median is x you must test all three orderings, and when the median is 4 you must discard solutions that leave the case's range. (2000 AMC 10 #23)
Problems, easiest first
Open any of them to try it here; the worked solution is on the problem's own page.