AMC 10 Step by Step
2017 AMC 10AProblem 18P16-20~4 minPrint

Amelia has a coin that lands heads with probability 13\tfrac{1}{3} , and Blaine has a coin that lands on heads with probability 25\tfrac{2}{5} . Amelia and Blaine alternately toss their coins until someone gets a head; the first one to get a head wins. All coin tosses are independent. Amelia goes first. The probability that Amelia wins is pq\tfrac{p}{q} , where pp and qq are relatively prime positive integers. What is qpq-p ?

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.