2014 AMC 10B Problem 6
Orvin went to the store with just enough money to buy balloons. When he arrived, he discovered that the store had a special sale on balloons: buy balloon at the regular price and get a second at off the regular price. What is the greatest number of balloons Orvin could buy?
Show solution without answering
Key insight
Measure money in regular balloon prices. On sale, a pair costs 1 + 2/3 = 5/3 prices, so 30 prices buy 18 pairs, which is 36 balloons.
Solution
1. Pick an easy unit. Say one balloon normally costs . Orvin can buy exactly balloons, so he has .
2. Price of a sale pair. The first balloon costs . The second is off, so it costs of a dollar. One pair costs
3. How many pairs? Three pairs cost . So every buys pairs, which is balloons.
4. Orvin has , so he buys pairs with nothing left over.
5. That is balloons.
The answer is .
Why this works
Using the regular price as the unit turns the budget into a plain number (). A "buy one, get one at a discount" deal repeats in pairs, so work out the cost of one pair and see how many pairs fit. It is also worth checking whether money is left over, since a leftover single balloon would cost full price; here the money runs out exactly.
Concise solution
A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.
Let one balloon regularly cost unit, so Orvin has units.
Under the sale, a pair of balloons costs units. The number of pairs he can afford is
which is balloons, using all his money exactly.
The answer is .
Review in the AoPS books
- Introduction to Algebra, Chapter 6: Ratios and Percents
- Introduction to Algebra, Chapter 7: Proportion (§7.1, §7.2, §7.3)
- Prealgebra, Chapter 13: Data and Statistics (§13.1)
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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.