AMC 10 Step by Step

2025 AMC 10A Problem 2

P1-10~2 minPrint

A box contains 1010 pounds of a nut mix that is 5050 percent peanuts, 2020 percent cashews, and 3030 percent almonds. A second nut mix containing 2020 percent peanuts, 4040 percent cashews, and 4040 percent almonds is added to the box resulting in a new nut mix that is 4040 percent peanuts. How many pounds of cashews are now in the box?

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Key insight

Follow only the peanuts. The peanut pounds must be 40 percent of the new total weight; that tells how much mix was added, and then count the cashews.

Solution

  1. Start with what is already in the box. 1010 pounds that are 50%50\% peanuts means 55 pounds of peanuts. 20%20\% cashews means 22 pounds of cashews. (The almonds, 33 pounds, will never matter.)
  1. We don't know how much of the second mix is poured in, so call it xx pounds. That xx pounds brings 0.2x0.2x pounds of peanuts and 0.4x0.4x pounds of cashews.

3. The only fact we are given about the final mix is about peanuts, so use peanuts to find xx. After mixing:
- peanuts: 5+0.2x5 + 0.2x pounds,
- total weight: 10+x10 + x pounds.

4. Peanuts are 40%40\% of the total, so
5+0.2x=0.4(10+x)=4+0.4x.5 + 0.2x = 0.4(10 + x) = 4 + 0.4x.
Subtract 44 and 0.2x0.2x from both sides: 1=0.2x1 = 0.2x, so x=5x = 5.

  1. Quick check: the box now has 1515 pounds with 5+1=65 + 1 = 6 pounds of peanuts, and 66 is 40%40\% of 1515. Good.
  1. Now answer the actual question, about cashews: the box has 2+0.4×5=2+2=42 + 0.4 \times 5 = 2 + 2 = 4 pounds of cashews.

The answer is (B) 4\boxed{\textbf{(B)}\ 4}.

Why this works

In a mixing problem, the pounds of one ingredient always equal its percent times the total weight. Pick the ingredient the problem tells you about (peanuts), write that one equation, and solve for the unknown amount. Then use the amount to answer whatever was really asked. Ingredients that are never mentioned in a condition, like the almonds here, can be ignored.

Alternative approach

Try the answer choices backwards. The cashews in the box are 2+0.4x2 + 0.4x. For choice (B), 2+0.4x=42 + 0.4x = 4 gives x=5x = 5. Then the peanuts are 5+0.2×5=65 + 0.2 \times 5 = 6 pounds out of 1515, which is exactly 40%40\%. So (B) works. (For (D), 2+0.4x=52 + 0.4x = 5 gives x=7.5x = 7.5, and peanuts would be 6.56.5 out of 17.517.5, about 37%37\%, which is wrong.)

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

The 1010 pounds already in the box consist of 55 pounds of peanuts, 22 pounds of cashews and 33 pounds of almonds.

Let xx be the number of pounds of the second mix added. It brings 0.2x0.2x pounds of peanuts and 0.4x0.4x pounds of cashews, and the box now holds 10+x10 + x pounds in total. The peanut condition says
5+0.2x10+x=0.4  ⟹  5+0.2x=4+0.4x  ⟹  1=0.2x  ⟹  x=5.\frac{5 + 0.2x}{10 + x} = 0.4 \implies 5 + 0.2x = 4 + 0.4x \implies 1 = 0.2x \implies x = 5.

Now return to the cashews: the box holds
2+0.4(5)=2+2=42 + 0.4(5) = 2 + 2 = 4
pounds of them.

The answer is (B) 4\boxed{\textbf{(B)}\ 4}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.