AMC 10 Step by Step

2014 AMC 10B Problem 5

P1-10~3 minPrint

Camden constructs a square window using 88 equal-size panes of glass, as shown. The ratio of the height to width for each pane is 5 :25 : 2 , and the borders around and between the panes are 22 inches wide. In inches, what is the side length of the square window? figure

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Key insight

Call the panes 2x wide and 5x tall. Across there are 4 panes and 5 borders, down there are 2 panes and 3 borders; the two totals must match.

Solution

1. Read the picture. The 88 panes sit in 44 columns and 22 rows.
2. Name the pane size. The height-to-width ratio is 5:25:2, so say each pane is 2x2x inches wide and 5x5x inches tall.
3. Measure across. Going left to right you pass a border, a pane, a border, a pane, a border, a pane, a border, a pane, a border. That is 44 panes and 55 borders:
width=4×2x+5×2=8x+10.\text{width} = 4 \times 2x + 5 \times 2 = 8x + 10.
4. Measure down. Going top to bottom you pass a border, a pane, a border, a pane, a border. That is 22 panes and 33 borders:
height=2×5x+3×2=10x+6.\text{height} = 2 \times 5x + 3 \times 2 = 10x + 6.
5. Use "square." The width and the height are equal: 8x+10=10x+68x + 10 = 10x + 6. Subtract 8x+68x + 6 from both sides to get 4=2x4 = 2x, so x=2x = 2.
6. The side is 8×2+10=268 \times 2 + 10 = 26 inches. (Check with the height: 10×2+6=2610 \times 2 + 6 = 26.)

The answer is (A) 26\boxed{\textbf{(A)}\ 26}.

Why this works

A ratio like 5:25:2 means the two lengths are 55 and 22 times some unknown number, so one letter handles both. The word "square" gives the equation: two different ways of measuring the side must agree. The only careful part is counting borders; with nn panes in a row there are always n+1n + 1 strips around and between them.

Alternative approach

Try the choices. With side 2626, the glass across is 26−5×2=1626 - 5 \times 2 = 16 inches, so each pane is 16÷4=416 \div 4 = 4 inches wide. The glass down is 26−3×2=2026 - 3 \times 2 = 20 inches, so each pane is 20÷2=1020 \div 2 = 10 inches tall. Since 10:4=5:210 : 4 = 5 : 2, choice (A) works.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

The figure shows the 88 panes in 44 columns and 22 rows. Let each pane be 2x2x wide and 5x5x tall.

Across the window there are 44 pane widths and 55 border strips (one on each edge and three between columns):
width=4(2x)+5(2)=8x+10.\text{width} = 4(2x) + 5(2) = 8x + 10.

Down the window there are 22 pane heights and 33 border strips:
height=2(5x)+3(2)=10x+6.\text{height} = 2(5x) + 3(2) = 10x + 6.

The window is square, so 8x+10=10x+68x + 10 = 10x + 6, giving x=2x = 2. The side length is 8(2)+10=268(2) + 10 = 26.

The answer is (A) 26\boxed{\textbf{(A)}\ 26}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.