2014 AMC 10A Problem 10
Five positive consecutive integers starting with have average . What is the average of consecutive integers that start with ?
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Key insight
The average of five consecutive whole numbers is the middle one. So b is a + 2, and the second list averages b + 2, which is a + 4.
Solution
Try a small case first. If , the five numbers are . Their sum is and their average is , which is the middle number. That always happens: the numbers are spread evenly around the middle one, so the ones below it and above it balance out.
- The first list is . Its middle number is , so .
- The second list starts at : . Its average is its middle number, .
- Put in : the average is .
Check with : then , and the list has average , which is .
The answer is .
Why this works
When numbers go up by the same step and there is an odd number of them, the average is the middle one, because each number below the middle is matched by one the same distance above it. Using that fact twice makes the problem a two-line calculation. Checking with a small value like is a quick way to be sure.
Concise solution
A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.
The five integers are evenly spaced, so their average is the middle one: .
The five consecutive integers starting with are , whose average is likewise the middle term . Substituting ,
The answer is .
Review in the AoPS books
- Introduction to Algebra, Chapter 6: Ratios and Percents
- Introduction to Number Theory, Chapter 1: Integers: The Basics
- Introduction to Algebra, Chapter 7: Proportion (§7.1, §7.2, §7.3)
- Introduction to Algebra, Chapter 20: Special Functions (§20.3)
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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.