AMC 10 Step by Step

2015 AMC 10A Problem 4

P1-10~2 minPrint

Pablo, Sofia, and Mia got some candy eggs at a party. Pablo had three times as many eggs as Sofia, and Sofia had twice as many eggs as Mia. Pablo decides to give some of his eggs to Sofia and Mia so that all three will have the same number of eggs. What fraction of his eggs should Pablo give to Sofia?

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Key insight

Only the ratio matters, so give Mia 1 egg, Sofia 2 and Pablo 6. Everyone should end with 3, so Sofia gets 1 of Pablo's 6 eggs.

Solution

The question asks for a fraction, so the actual number of eggs does not matter. Pick the smallest numbers that fit the story.

  1. Give Mia 11 egg. Sofia has twice as many, so 22 eggs. Pablo has three times Sofia's, so 3×2=63 \times 2 = 6 eggs.
  2. All together they have 1+2+6=91 + 2 + 6 = 9 eggs. For everyone to have the same number, each person must end with 9÷3=39 \div 3 = 3 eggs.
  3. Sofia goes from 22 to 33, so Pablo gives her 11 egg. (Mia goes from 11 to 33, so she gets 22. Pablo keeps 6−1−2=36 - 1 - 2 = 3. Good.)
  4. The question asks what fraction of Pablo's eggs goes to Sofia: 11 egg out of his 66, which is 16\frac{1}{6}.

The answer is (B) 16\boxed{\textbf{(B)}\ \frac{1}{6}}.

Why this works

When only ratios are given and only a fraction is asked, choose easy numbers that fit the ratios. That turns the story into small, concrete arithmetic. Before answering, reread the question: here it wants Sofia's share only, measured against Pablo's starting pile.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Only ratios matter, so choose convenient numbers. Let Mia have 11 egg. Then Sofia has 22 and Pablo has 3⋅2=63 \cdot 2 = 6.

The total is 1+2+6=91 + 2 + 6 = 9 eggs, so after the redistribution each person holds 33. Sofia must go from 22 to 33, receiving 11 egg from Pablo. (Mia receives 22.)

Pablo gives Sofia 11 of his 66 eggs, which is the fraction 16\frac{1}{6}.

The answer is (B) 16\boxed{\textbf{(B)}\ \frac{1}{6}}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.