AMC 10 Step by Step

2023 AMC 10B Problem 5

P1-10~2 minPrint

Maddy and Lara see a list of numbers written on a blackboard. Maddy adds 33 to each number in the list and finds that the sum of her new numbers is 4545 . Lara multiplies each number in the list by 33 and finds that the sum of her new numbers is also 4545 . How many numbers are written on the blackboard?

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Key insight

Tripling every number triples the total, so the original total is 15. Adding 3 to every number adds 3 once for each number, and that extra is 30.

Solution

We never need the actual numbers. We only need to know what each girl's change does to the total.

1. Lara's clue gives the total. If every number is multiplied by 33, the total is multiplied by 33 too. (For example, 2+5=72 + 5 = 7 and 6+15=216 + 15 = 21.) Lara's total is 4545, so the original total is
45÷3=15.45 \div 3 = 15.
2. Maddy's clue gives the count. If every number gets 33 more, the total goes up by 33 once for each number. Her total is 4545, which is 3030 more than the original 1515.
3. Count the numbers. Each number added 33, and together they added 3030, so there are
30÷3=10 numbers.30 \div 3 = 10 \text{ numbers}.

The answer is (A) 10\boxed{\textbf{(A)}\ 10}.

Why this works

Two rules about totals do all the work. Multiplying every number by kk multiplies the total by kk. Adding cc to every number adds cc times (how many numbers there are) to the total. Lara's clue fixes the total, and Maddy's clue then turns the total into a count.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Let there be nn numbers with sum SS.

Lara triples every number, so her sum is 3S=453S = 45, giving S=15S = 15.

Maddy adds 33 to each of the nn numbers, which raises the sum by 3n3n: S+3n=45S + 3n = 45. With S=15S = 15 this gives 3n=303n = 30, so n=10n = 10.

The answer is (A) 10\boxed{\textbf{(A)}\ 10}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.