AMC 10 Step by Step

2023 AMC 10B Problem 4

P1-10~2 minPrint

Jackson's paintbrush makes a narrow strip with a width of 6.56.5 millimeters. Jackson has enough paint to make a strip 2525 meters long. How many square centimeters of paper could Jackson cover with paint?

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Key insight

Change both lengths into centimeters before multiplying: 6.5 mm is 0.65 cm and 25 m is 2500 cm. Then the area comes out directly in square centimeters.

Solution

The painted strip is a long, thin rectangle, so its area is width times length. The problem mixes three units, so turn everything into centimeters first.

1. Width. There are 1010 millimeters in a centimeter, so
6.5 mm=0.65 cm.6.5 \text{ mm} = 0.65 \text{ cm}.
2. Length. There are 100100 centimeters in a meter, so
25 m=2500 cm.25 \text{ m} = 2500 \text{ cm}.
3. Area. Multiply:
0.65×2500=1625 square centimeters.0.65 \times 2500 = 1625 \text{ square centimeters}.
(One easy way: 0.65×2500=65×25=16250.65 \times 2500 = 65 \times 25 = 1625.)

The answer is (C) 1,625\boxed{\textbf{(C)}\ 1{,}625}.

Why this works

When the answer must be in a certain unit of area, put every length in the matching unit of length first. Then the area formula gives the right unit with no more work. Changing units after you already have an area is where mistakes happen, because 11 square centimeter is 100100 square millimeters, not 1010.

Alternative approach

Estimate. The strip is a little more than half a centimeter wide and 25002500 cm long, so the area is a bit more than half of 25002500, which is 12501250, but less than 25002500. Only 1,6251{,}625 is in that range.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

The painted strip is a long thin rectangle. Convert both sides to centimeters before multiplying:
6.5 mm=0.65 cm,25 m=2500 cm.6.5 \text{ mm} = 0.65 \text{ cm}, \qquad 25 \text{ m} = 2500 \text{ cm}.
The area is
0.65×2500=1625 cm2.0.65 \times 2500 = 1625 \text{ cm}^2.

The answer is (C) 1,625\boxed{\textbf{(C)}\ 1{,}625}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.