2023 AMC 10B Problem 4
Jackson's paintbrush makes a narrow strip with a width of millimeters. Jackson has enough paint to make a strip meters long. How many square centimeters of paper could Jackson cover with paint?
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Key insight
Change both lengths into centimeters before multiplying: 6.5 mm is 0.65 cm and 25 m is 2500 cm. Then the area comes out directly in square centimeters.
Solution
The painted strip is a long, thin rectangle, so its area is width times length. The problem mixes three units, so turn everything into centimeters first.
1. Width. There are millimeters in a centimeter, so
2. Length. There are centimeters in a meter, so
3. Area. Multiply:
(One easy way: .)
The answer is .
Why this works
When the answer must be in a certain unit of area, put every length in the matching unit of length first. Then the area formula gives the right unit with no more work. Changing units after you already have an area is where mistakes happen, because square centimeter is square millimeters, not .
Alternative approach
Estimate. The strip is a little more than half a centimeter wide and cm long, so the area is a bit more than half of , which is , but less than . Only is in that range.
Concise solution
A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.
The painted strip is a long thin rectangle. Convert both sides to centimeters before multiplying:
The area is
The answer is .
Review in the AoPS books
- Intermediate Counting & Probability, Chapter 2: Sets and Logic (§2.2, §2.3)
- Introduction to Geometry, Chapter 8: Quadrilaterals
- Prealgebra, Chapter 7: Ratios, Conversions, and Rates (§7.4)
- Introduction to Geometry, Chapter 9: Polygons (§9.3)
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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.