AMC 10 Step by Step

2006 AMC 10B Problem 3

P1-10~1 minPrint

A football game was played between two teams, the Cougars and the Panthers. The two teams scored a total of 3434 points, and the Cougars won by a margin of 1414 points. How many points did the Panthers score?

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Key insight

Take away the 14-point winning margin from the total 34. What is left, 20, is split equally between the two teams, so the losing team has 10.

Solution

  1. The Cougars won, so they scored 1414 more points than the Panthers.
  2. Picture taking those extra 1414 points away from the Cougars. Then both teams have the same score, and the total drops to 34−14=2034 - 14 = 20.
  3. Two equal scores that add to 2020 are 1010 each. That equal score is exactly the Panthers' score, since we only took points away from the Cougars.
  4. Check: the Cougars scored 10+14=2410 + 14 = 24. Then 24+10=3424 + 10 = 34 and 24−10=1424 - 10 = 14. Both facts match.

The Panthers scored (A) 10\boxed{\textbf{(A)}\ 10}.

Why this works

When you know the total of two amounts and how far apart they are, remove the difference, split what is left in half, and you have the smaller amount. Add the difference back to get the larger one. Always reread the question to see which of the two it wants.

Alternative approach

With letters: let cc be the Cougars' score and pp the Panthers'. Then c+p=34c + p = 34 and c−p=14c - p = 14. Adding the two equations gives 2c=482c = 48, so c=24c = 24, and then p=34−24=10p = 34 - 24 = 10.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Let cc and pp be the Cougars' and Panthers' scores. We know c+p=34c + p = 34 and c−p=14c - p = 14.

Subtracting the second equation from the first eliminates cc:
2p=34−14=20,p=10.2p = 34 - 14 = 20, \qquad p = 10.
(Then c=24c = 24, and indeed 24+10=3424 + 10 = 34 and 24−10=1424 - 10 = 14.)

The Panthers scored (A) 10\boxed{\textbf{(A)}\ 10}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.