AMC 10 Step by Step
2016 AMC 10AProblem 19P16-20~5 minPrint

In rectangle ABCD,ABCD, AB=6AB=6 and BC=3BC=3 . Point EE between BB and CC , and point FF between EE and CC are such that BE=EF=FCBE=EF=FC . Segments AE\overline{AE} and AF\overline{AF} intersect BD\overline{BD} at PP and QQ , respectively. The ratio BP:PQ:QDBP:PQ:QD can be written as r:s:tr:s:t where the greatest common factor of r,sr,s and tt is 1. What is r+s+tr+s+t ?

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.