2010 AMC 10A Problem 2
Four identical squares and one rectangle are placed together to form one large square as shown. The length of the rectangle is how many times as large as its width?

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Key insight
Give the small square side 1. The big square is then 4 by 4, and the rectangle under the row is 4 long and 3 tall.
Solution
Give the small squares an easy size and read every other length off the picture.
- Say each small square has side .
- The four small squares sit side by side across the top, so the top edge of the big square is long. A square has equal sides, so the big square is by .
- The rectangle fills the rest of the big square, under the row of small squares. Its long side runs all the way across: .
- Its short side is the big square's height minus the row of small squares on top: .
- So the length is times the width.
Using side instead of gives , the same ratio, so the choice of does not matter.
The answer is .
Why this works
When a figure is built from identical pieces, give the smallest piece a size and count your way to every other length. A ratio does not depend on the actual size, so picking side is safe and makes the numbers easy.
Concise solution
A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.
Let each small square have side . The four small squares sit in a row along the top edge, so the large square has side .
The rectangle fills everything below that row. Its length (horizontal) is the full side of the large square, . Its width (vertical) is what remains after removing the row of small squares: .
Therefore the length is times the width.
The answer is .
Review in the AoPS books
- Introduction to Geometry, Chapter 8: Quadrilaterals
- Introduction to Algebra, Chapter 6: Ratios and Percents
- Introduction to Geometry, Chapter 9: Polygons (§9.3)
- Introduction to Algebra, Chapter 7: Proportion (§7.1, §7.2, §7.3)
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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.