AMC 10 Step by Step

2021 AMC Fall 10A Problem 2

P1-10~1 minPrint

Menkara has a 4×64 \times 6 index card. If she shortens the length of one side of this card by 11 inch, the card would have area 1818 square inches. What would the area of the card be in square inches if instead she shortens the length of the other side by 11 inch?

Log in to save your progress.
Show solution without answering

Key insight

Try both sides. Only cutting the 4-inch side gives 3 by 6 = 18, so the other side is the 6-inch side, and 4 by 5 = 20.

Solution

The card is 44 by 66, so there are only two sides she could shorten. Try both and see which one gives 1818.

  1. Shorten the 44-inch side: the card becomes 33 by 66, with area 3×6=183 \times 6 = 18.
  2. Shorten the 66-inch side: the card becomes 44 by 55, with area 4×5=204 \times 5 = 20.
  3. The problem says the area would be 1818, so the first change was to the 44-inch side.
  4. The question asks about the other side, which is the 66-inch side. From step 2, that gives area 2020.

The answer is (E) 20\boxed{\textbf{(E)}\ 20}.

Why this works

The area 1818 is not extra information. It tells you which side was shortened first. When a problem allows only two possibilities, work out both, and let the fact the problem gives you choose between them.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Test which side was shortened. Shortening the 44-inch side gives a 3×63 \times 6 card of area 1818; shortening the 66-inch side gives a 4×54 \times 5 card of area 2020. Since the problem says the result was 1818, the first change was to the 44-inch side.

"The other side" is therefore the 66-inch side, and shortening it by 11 inch produces a 4×54 \times 5 card with area 4⋅5=204 \cdot 5 = 20.

The answer is (E) 20\boxed{\textbf{(E)}\ 20}.

Review in the AoPS books

Similar problems

Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.