AMC 10 Step by Step

2009 AMC 10B Problem 1

P1-10~1 minPrint

Each morning of her five-day workweek, Jane bought either a 5050 -cent muffin or a 7575 -cent bagel. Her total cost for the week was a whole number of dollars. How many bagels did she buy?

Log in to save your progress.
Show solution without answering

Key insight

Five muffins cost 2 dollars and 50 cents, and each swap to a bagel adds 25 cents, so two swaps reach a whole dollar amount.

Solution

There are only five possible answers, so start from the cheapest week and see how the total changes.

  1. If Jane bought no bagels, she bought 55 muffins for 5×50=2505 \times 50 = 250 cents, which is $2.50\$2.50. That is not a whole number of dollars.
  2. Each time one muffin is replaced by a bagel, the total goes up by 75−50=2575 - 50 = 25 cents.
  3. Make a table of the totals:
Bagels001122334455
Total (cents)250250275275300300325325350350375375
  1. A whole number of dollars means the total in cents is a multiple of 100100. Only 300300 cents works, and that happens with 22 bagels.
  2. Check: 22 bagels cost $1.50\$1.50 and 33 muffins cost $1.50\$1.50, for $3.00\$3.00 in all.

The answer is (B) 2\boxed{\textbf{(B)}\ 2}.

Why this works

When there are two kinds of items and a fixed total number of them, start with all of one kind and count how much each swap changes the total. Here every swap adds the same 2525 cents, so the totals go up in equal steps and you can spot the one that lands on a whole dollar.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Suppose Jane bought bb bagels and 5−b5 - b muffins. In cents her total is
75b+50(5−b)=250+25b.75b + 50(5 - b) = 250 + 25b.
This must be a multiple of 100100. Since 250250 already leaves a remainder of 5050, the term 25b25b must contribute another 5050 (or 150150, 250250, and so on). With 0≤b≤50 \le b \le 5 the only option is 25b=5025b = 50, so b=2b = 2.

Check: two bagels and three muffins cost 1.50+1.50=$3.001.50 + 1.50 = \$3.00.

The answer is (B) 2\boxed{\textbf{(B)}\ 2}.

Review in the AoPS books

Similar problems

Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.