AMC 10 Step by Step
2020 AMC 10AProblem 12P11-15~4 minPrint

Triangle AMCAMC is isosceles with AM=ACAM = AC . Medians MV\overline{MV} and CU\overline{CU} are perpendicular to each other, and MV=CU=12MV=CU=12 . What is the area of AMC?\triangle AMC?

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.