AMC 10 Step by Step

2011 AMC 10A Problem 1

P1-10~1 minPrint

A cell phone plan costs $20\$20 each month, plus 55 ¢ per text message sent, plus 1010 ¢ for each minute used over 3030 hours. In January Michelle sent 100100 text messages and talked for 30.530.5 hours. How much did she have to pay?

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Key insight

Split the bill into three parts. Only the extra half hour costs money, and half an hour is 30 minutes at 10 cents each.

Solution

The bill has three parts, so work out each part on its own and add them at the end.

  1. The monthly fee. This is $20\$20, no matter what.
  2. The texts. Michelle sent 100100 texts at 55 cents each. That is 100×5=500100 \times 5 = 500 cents, which is $5\$5.
  3. The extra talking time. The first 3030 hours are included. She talked 30.530.5 hours, so only 30.5−30=0.530.5 - 30 = 0.5 hour is extra.
  4. The charge is per minute, so change the half hour into minutes: 0.50.5 hour is 3030 minutes. At 1010 cents a minute, that is 30×10=30030 \times 10 = 300 cents, which is $3\$3.
  5. Add the parts. 20+5+3=2820 + 5 + 3 = 28 dollars.

The answer is (D) $28.00\boxed{\textbf{(D)}\ \$28.00}.

Why this works

A bill like this is a fixed fee plus a few "number times price" pieces. The only danger is mixing units: cents with dollars, or hours with minutes. Put every piece into the same unit before you add. And when a plan says "over 30 hours", you pay only for the part above 30 hours.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Add the three parts of the bill separately.

Fixed charge: $20\$20.

Texts: 100100 messages at 55 cents each is 500500 cents, or $5\$5.

Overage: Michelle talked 30.5−30=0.530.5 - 30 = 0.5 hours beyond the free allowance, and 0.50.5 hours is 3030 minutes. At 1010 cents per minute that is 300300 cents, or $3\$3.

Total: 20+5+3=2820 + 5 + 3 = 28 dollars.

The answer is (D) $28.00\boxed{\textbf{(D)}\ \$28.00}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.