AMC 10 Step by Step

2011 AMC 10A Problem 2

P1-10~1 minPrint

A small bottle of shampoo can hold 35 milliliters of shampoo, whereas a large bottle can hold 500 milliliters of shampoo. Jasmine wants to buy the minimum number of small bottles necessary to completely fill a large bottle. How many bottles must she buy?

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Key insight

Fourteen small bottles hold only 490 milliliters, which is not quite 500, so she needs one more bottle.

Solution

We want the fewest small bottles that together hold at least 500500 milliliters.

  1. Estimate first: 35×10=35035 \times 10 = 350, which is too little, so the answer is more than 1010.
  2. Try 1414 bottles: 35×14=49035 \times 14 = 490 milliliters. That is 1010 milliliters short of 500500, so 1414 is not enough.
  3. Try 1515 bottles: 35×15=52535 \times 15 = 525 milliliters. That is at least 500500, so 1515 bottles fill the large bottle (with some left over).

So the smallest number that works is 1515.

The answer is (E) 15\boxed{\textbf{(E)}\ 15}.

Why this works

"Completely fill" means the total has to reach the target. If 500÷35500 \div 35 is not a whole number, the leftover part still needs a whole extra bottle, so you always round up. Whether you round up or down comes from the wording of the question, not from how big the remainder is.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

We need the smallest whole number kk with 35k≥50035k \ge 500.

Compute 35⋅14=49035 \cdot 14 = 490, which is less than 500500, so 1414 bottles do not suffice. Then 35⋅15=525≥50035 \cdot 15 = 525 \ge 500, so 1515 bottles are enough.

Equivalently, 50035=1427\frac{500}{35} = 14\frac{2}{7}, and since a fraction of a bottle cannot be bought, round up to 1515.

The answer is (E) 15\boxed{\textbf{(E)}\ 15}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.