AMC 10 Step by Step

2008 AMC 10A Problem 12

P11-15~2 minPrint

In a collection of red, blue, and green marbles, there are 25%25\% more red marbles than blue marbles, and there are 60%60\% more green marbles than red marbles. Suppose that there are rr red marbles. What is the total number of marbles in the collection?

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Key insight

25% more red than blue means red is 1.25 times blue, so blue is red divided by 1.25, which is 0.8r. Green is 1.6r, and the total is 3.4r.

Solution

Try concrete numbers first to see how the percents work.

  1. Suppose there are 44 blue marbles. "25%25\% more red than blue" means red is 44 plus a quarter of 44, so 55 red.
  2. "60%60\% more green than red" means green is 55 plus 60%60\% of 55, which is 5+3=85 + 3 = 8 green.
  3. Total: 4+5+8=174 + 5 + 8 = 17 marbles, and 17÷5=3.417 \div 5 = 3.4. So the total is 3.43.4 times the number of red marbles.

Now the same thing with rr red marbles.

4. Red is 1.251.25 times blue, so blue is red divided by 1.251.25:
blue=r1.25=4r5=0.8r.\text{blue} = \frac{r}{1.25} = \frac{4r}{5} = 0.8r.
(In the example: 5÷1.25=45 \div 1.25 = 4. Blue is 20%20\% fewer than red, not 25%25\% fewer.)
5. Green is 60%60\% more than red: green=1.6r\text{green} = 1.6r.
6. Add them up:
r+0.8r+1.6r=3.4r.r + 0.8r + 1.6r = 3.4r.

The answer is (C) 3.4r\boxed{\textbf{(C)}\ 3.4r}.

Why this works

"25%25\% more than blue" measures the 25%25\% from the blue count, so red =1.25×= 1.25 \times blue. To go back from red to blue you must divide by 1.251.25; subtracting 25%25\% of red is a different, wrong step. Trying a small example, like 44 blue and 55 red, makes the difference easy to see.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Let bb and gg be the numbers of blue and green marbles.

"25%25\% more red than blue" means r=1.25br = 1.25b, so
b=r1.25=4r5=0.8r.b = \frac{r}{1.25} = \frac{4r}{5} = 0.8r.

"60%60\% more green than red" means g=1.6rg = 1.6r.

The total is
r+b+g=r+0.8r+1.6r=3.4r.r + b + g = r + 0.8r + 1.6r = 3.4r.

The answer is (C) 3.4r\boxed{\textbf{(C)}\ 3.4r}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.