AMC 10 Step by Step

2006 AMC 10B Problem 9

P1-10~1 minPrint

Francesca uses 100100 grams of lemon juice, 100100 grams of sugar, and 400400 grams of water to make lemonade. There are 2525 calories in 100100 grams of lemon juice and 386386 calories in 100100 grams of sugar. Water contains no calories. How many calories are in 200200 grams of her lemonade?

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Key insight

The batch weighs 600 grams and has 411 calories. A 200-gram glass is one third of the batch, so it has 411 divided by 3 = 137.

Solution

  1. Weigh the whole batch: 100+100+400=600100 + 100 + 400 = 600 grams. The water has no calories, but it still counts toward the weight.
  2. Count all the calories: 2525 from lemon juice, 386386 from sugar, and 00 from water, for a total of 25+386=41125 + 386 = 411 calories.
  3. The lemonade is mixed evenly, so every gram has the same share of calories. A 200200-gram glass is 200600=13\frac{200}{600} = \frac{1}{3} of the batch.
  4. So it has one third of the calories: 411÷3=137411 \div 3 = 137.

The answer is (B) 137\boxed{\textbf{(B)}\ 137}.

Why this works

In a well-mixed drink, any part of it has the same calories per gram as the whole batch. So find the totals for the whole batch (every ingredient's weight, even the ones with no calories), then take the right fraction.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Total mass of the lemonade: 100+100+400=600100 + 100 + 400 = 600 grams.

Total calories: 2525 from the lemon juice, 386386 from the sugar, 00 from the water, so 411411 calories.

A 200200-gram serving is 200600=13\frac{200}{600} = \frac{1}{3} of the batch, so it contains 4113=137\frac{411}{3} = 137 calories.

The answer is (B) 137\boxed{\textbf{(B)}\ 137}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.