AMC 10 Step by Step

2006 AMC 10B Problem 16

P16-20~3 minPrint

Leap Day, February 2929 , 20042004 , occurred on a Sunday. On what day of the week will Leap Day, February 2929 , 20202020 , occur?

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Key insight

A normal year moves the weekday 1 forward; a year with a leap day moves it 2. That is 12 + 8 = 20, which is 6 past Sunday.

Solution

  1. See how one year moves the weekday. A normal year has 365365 days, and 365=52⋅7+1365 = 52 \cdot 7 + 1. So after 5252 full weeks there is 11 day left over, and the same date lands one weekday later.
  2. If the year you move through includes a February 2929, it has 366366 days, which is 22 days past a whole number of weeks. The weekday moves 22 later.
  3. Going from February 2929, 20042004 to February 2929, 20202020 is 1616 one-year steps. List the leap days you pass through: February 2929 of 20082008, 20122012, 20162016 and 20202020. That is 44 steps that move by 22, and the other 1212 steps move by 11.
  4. Total shift: 12⋅1+4⋅2=2012 \cdot 1 + 4 \cdot 2 = 20 days forward.
  5. Every 77 days the weekday repeats, so take away whole weeks: 20−14=620 - 14 = 6. Six days after Sunday is Saturday.

The answer is (E) Saturday\boxed{\textbf{(E)}\ \textrm{Saturday}}.

Why this works

For weekday questions only the leftover after whole weeks matters, so think of a year as "11 extra day" (or 22 for a leap year) instead of 365365 days. The careful part is counting leap days: count every February 2929 after the starting date, up to and including the ending date.

Alternative approach

Count the days directly: 16⋅365+4=584416 \cdot 365 + 4 = 5844. Now 7⋅835=58457 \cdot 835 = 5845, so 58445844 is one day short of a whole number of weeks. The weekday is one day before Sunday, which is Saturday.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Moving a date forward one ordinary year adds 365=52⋅7+1365 = 52 \cdot 7 + 1 days, which pushes the weekday forward by 11. If the year crossed contains a February 2929, the jump is 366366 days and the weekday moves forward by 22.

From February 29, 2004 to February 29, 2020 is 1616 years. The leap days passed along the way are February 29 of 20082008, 20122012, 20162016, and 20202020: four of them (none of these years is a century exception). So 44 of the 1616 yearly steps shift by 22 and the other 1212 shift by 11:
12⋅1+4⋅2=20≡6(mod7).12 \cdot 1 + 4 \cdot 2 = 20 \equiv 6 \pmod 7.

Six days after Sunday is Saturday (equivalently, one day back).

The answer is (E) Saturday\boxed{\textbf{(E)}\ \textrm{Saturday}}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.