AMC 10 Step by Step

2016 AMC 10B Problem 4

P1-10~2 minPrint

Zoey read 1515 books, one at a time. The first book took her 11 day to read, the second book took her 22 days to read, the third book took her 33 days to read, and so on, with each book taking her 11 more day to read than the previous book. Zoey finished the first book on a Monday, and the second on a Wednesday. On what day of the week did she finish her 1515 th book?

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Key insight

Book 15 is finished on day 1 + 2 + ... + 15 = 120. Day 120 is 119 days after day 1, and 119 is exactly 17 weeks.

Solution

Give each day a number. Call the Monday when she finished book 11 "day 11."

1. Book 22 takes 22 more days, so it is finished on day 1+2=31 + 2 = 3. Day 33 is two days after Monday, a Wednesday. That matches the problem, so the numbering is right.
2. Keep going. Book 33 ends on day 1+2+3=61 + 2 + 3 = 6, book 44 on day 1+2+3+4=101 + 2 + 3 + 4 = 10, and so on. Book 1515 ends on day
1+2+3+⋯+15=15⋅162=120.1 + 2 + 3 + \cdots + 15 = \frac{15 \cdot 16}{2} = 120.
3. Day 120120 is 120−1=119120 - 1 = 119 days after day 11.
4. The weekday repeats every 77 days, and 119=7⋅17119 = 7 \cdot 17. So 119119 days is exactly 1717 weeks, and we land on the same weekday as day 11.

The answer is (B) Monday\boxed{\textbf{(B)}\ \text{Monday}}.

Why this works

"Finished book nn" means "the total of all reading days so far," so the finishing days are the running totals 1,3,6,10,…1, 3, 6, 10, \ldots. For the weekday, only the remainder when you divide the number of days between two dates by 77 matters. Be careful to count the days between the dates, which is one less than the day number.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Number the days so that day 11 is the Monday on which book 11 is finished. Book 22 takes two more days and is finished on day 33, a Wednesday, which matches the statement.

Book nn is finished on day 1+2+⋯+n1 + 2 + \cdots + n, so book 1515 is finished on day
1+2+⋯+15=15⋅162=120.1 + 2 + \cdots + 15 = \frac{15 \cdot 16}{2} = 120.

Day 120120 is 119119 days after day 11. Since 119=7⋅17119 = 7 \cdot 17, that is exactly 1717 weeks later, so day 120120 falls on the same weekday as day 11.

The answer is (B) Monday\boxed{\textbf{(B)}\ \text{Monday}}.

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.