AMC 10 Step by Step

2001 AMC 10 Problem 9

P1-10~3 minPrint

The state income tax where Kristin lives is charged at the rate of p%p\% of the first $28000\$28000 of annual income plus (p+2)%(p + 2)\% of any amount above $28000\$28000 . Kristin noticed that the state income tax she paid amounted to (p+0.25)%(p + 0.25)\% of her annual income. What was her annual income?

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Key insight

See the tax as p% on everything plus an extra 2% above $28000. The p% parts cancel, so that extra 2% equals 0.25% of her income.

Solution

1. First, her income must be more than $28000\$28000. If it were $28000\$28000 or less, all of it would be taxed at exactly p%p\%, not (p+0.25)%(p + 0.25)\%.
2. Call her income II. Split it into the first $28000\$28000 and the extra part, I−28000I - 28000.
3. The extra part is taxed at (p+2)%(p + 2)\%, which is p%p\% plus another 2%2\%. So her tax is the same as:
- p%p\% on all of her income, plus
- an extra 2%2\% on the part above $28000\$28000.
4. The problem also says her tax is (p+0.25)%(p + 0.25)\% of her income, which is:
- p%p\% on all of her income, plus
- an extra 0.25%0.25\% on all of her income.
5. The first lines of steps 3 and 4 are the same, so the second lines must be equal too:
2% of (I−28000)=0.25% of I.2\% \text{ of } (I - 28000) = 0.25\% \text{ of } I.
6. Multiply both sides by 100100 to remove the percent signs: 2(I−28000)=0.25I2(I - 28000) = 0.25I.
7. Expand: 2I−56000=0.25I2I - 56000 = 0.25I. Move the II terms together: 1.75I=560001.75I = 56000.
8. Divide: I=56000÷1.75=32000I = 56000 \div 1.75 = 32000.
9. Check: the extra part is $4000\$4000, and 2%2\% of 40004000 is $80\$80. Also 0.25%0.25\% of 3200032000 is $80\$80. They match.

The answer is (B) $32000\boxed{\textbf{(B)}\ \$32000}.

Why this works

A tax with two rates can always be seen as "the lower rate on everything, plus a surcharge on the amount over the cutoff." Seen that way, the unknown rate pp appears on both sides and cancels, so you never need to know it. When a letter you cannot find appears on both sides, look for a way to make it cancel.

Alternative approach

Test the choices using the surcharge idea from step 5: compare 2%2\% of the amount over $28000\$28000 with 0.25%0.25\% of the income.

Income2%2\% of excess0.25%0.25\% of income
$32000\$32000$80\$80$80\$80
$35000\$35000$140\$140$87.50\$87.50
$42000\$42000$280\$280$105\$105

Only $32000\$32000 balances.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Let Kristin's income be II dollars. If I≤28000I \le 28000 her rate would be exactly p%p\%, not (p+0.25)%(p+0.25)\%, so I>28000I > 28000. Her tax, in dollars, is
p100⋅28000+p+2100(I−28000).\frac{p}{100}\cdot 28000 + \frac{p+2}{100}(I - 28000).
Regroup: this equals p100⋅I+2100(I−28000)\frac{p}{100}\cdot I + \frac{2}{100}(I - 28000), i.e. p%p\% of everything plus an extra 2%2\% of the part above 2800028000.

The tax is also p+0.25100I=p100I+0.25100I\frac{p+0.25}{100} I = \frac{p}{100} I + \frac{0.25}{100} I. Comparing, the p%p\% pieces cancel and
2(I−28000)=0.25I⟹1.75I=56000⟹I=32000.2(I - 28000) = 0.25 I \quad\Longrightarrow\quad 1.75 I = 56000 \quad\Longrightarrow\quad I = 32000.

The answer is (B) $32000\boxed{\textbf{(B)}\ \$32000}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site. Also appeared as 2001 12 #3.