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2025 AMC 10B Problem 6

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2025 AMC 10B Problem 6AMC 10 Step by Step

Name: Date: September 13, 2026

Coordinate Geometry · difficulty 2 of 5 · about 3 min · position P1-10

The line $y = \frac{1}{3}x + 1$ divides the square region defined by $0 \leq x \leq 2$ and $0 \leq y \leq 2$ into an upper and lower region. The line $x=a$ divides the lower region into two regions of equal area. Then $a$ can be written as $\sqrt{s} - t$ , where $s$ and $t$ are positive integers. What is $s+t$ ?

A)
$18$
B)
$19$
C)
$20$
D)
$21$
E)
$22$

2025 AMC 10B Problem 6

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