Amy, Bomani, Charlie, and Daria work in a chocolate factory. On Monday Amy, Bomani, and Charlie started working at and were able to pack , , and packages, respectively, every minutes. At some later time, Daria joined the group, and Daria was able to pack packages every minutes. Together, they finished packing packages at exactly . At what time did Daria join the group?
- A)
- B)
- C)
- D)
- E)
Answer
A
Key insight
Amy, Bomani and Charlie pack 10 per 3 minutes for all 105 minutes (350 packages); Daria's remaining 100 at 5 per 4 minutes take 80 minutes, ending at 2:45.
Solution
Amy, Bomani and Charlie together pack packages every minutes. From 1:00 PM to 2:45 PM is minutes, which is blocks of minutes, so the three of them pack packages.
That leaves packages for Daria. She packs every minutes, so packages take minutes.
Daria worked the last minutes, so she joined minutes before 2:45 PM, at 1:25 PM.
The answer is .
Why this works
Separate the contributions: the original trio works the entire interval, so their output is fixed; whatever is left over must be Daria's, and dividing by her rate gives her working time. Counting backwards from the known end time avoids setting up an unknown start time at all.
Alternative approach
Let Daria work minutes. Then , so and ; she started at PM.
The trap
Applying Daria's rate to the whole 1:00–2:45 window, or miscounting that window as 145 minutes instead of 105.
Common mistakes
- Applying Daria's rate to the whole 1:00–2:45 window, or miscounting that window as 145 minutes instead of 105.
- Using per-minute rates carelessly (e.g. per minute instead of per minutes).
Techniques
Set up the equation/formula and compute; no special trick needed · Start from the end state / desired conclusion and reverse