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2023 AMC 10B Problem 15

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2023 AMC 10B Problem 15AMC 10 Step by Step
Name:                             Date: September 13, 2026
Number Properties · difficulty 3 of 5 · about 5 min · position P11-15

What is the least positive integer mm such that m⋅2!⋅3!⋅4!⋅5!…16!m \cdot 2! \cdot 3!\cdot 4!\cdot 5! \dots 16! is a perfect square?

  1. A)

    3030

  2. B)

    3003030030

  3. C)

    7070

  4. D)

    14301430

  5. E)

    10011001

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