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2020 AMC 10A Problem 12

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2020 AMC 10A Problem 12AMC 10 Step by Step
Name:                             Date: September 13, 2026
Triangle Centers & Cevians · difficulty 3 of 5 · about 4 min · position P11-15

Triangle AMCAMC is isosceles with AM=ACAM = AC . Medians MV‾\overline{MV} and CU‾\overline{CU} are perpendicular to each other, and MV=CU=12MV=CU=12 . What is the area of △AMC?\triangle AMC?

figure

  1. A)

    4848

  2. B)

    7272

  3. C)

    9696

  4. D)

    144144

  5. E)

    192192

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