In a high school with students, of the seniors play a musical instrument, while of the non-seniors do not play a musical instrument. In all, of the students do not play a musical instrument. How many non-seniors play a musical instrument?
- A)
- B)
- C)
- D)
- E)
Answer
B
Key insight
Count non-players: 60% of seniors plus 30% of non-seniors equals 46.8% of 500, which pins down the split and then 70% of non-seniors play.
Solution
Work entirely with the students who do not play. Let be the number of seniors, so there are non-seniors.
- Seniors who do not play: of , or .
- Non-seniors who do not play: of , or .
- Total non-players: of , or .
So
There are non-seniors, and of them play: .
The answer is .
Why this works
Two of the three percentages describe non-players, so converting everything to the "do not play" category gives a single linear equation with no translation errors. Once the group sizes are known, the requested count is one more percentage step. Choose the category that makes the most given data line up.
Alternative approach
Test choice (B) directly: playing non-seniors at a rate means non-seniors and seniors. Non-players: . It checks.
The trap
Mixing 'play' and 'do not play' percentages, for example using 40% of seniors as non-players, and then answering 66 or 220.
Common mistakes
- Mixing 'play' and 'do not play' percentages, for example using 40% of seniors as non-players, and then answering 66 or 220.
- Stopping at , the number of non-seniors, instead of taking of it.
Techniques
Set up the equation/formula and compute; no special trick needed