2013 AMC 10B Problem 4
When counting from to , is the number counted. When counting backwards from to , is the number counted. What is ?
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Key insight
Counting down from 201 to 53 counts both end numbers, so the count is 201 minus 53, plus 1.
Solution
1. First see the rule on a tiny example. Count down from to : you say . That is numbers, but . You need one more than the difference, because both ends get said.
2. Test the rule on the fact given in the problem. Counting up from , the number is said st. That matches.
3. Now count down from . The numbers said, up to and including , are . How many is that?
So is the th number said.
The answer is .
Why this works
To count the whole numbers from to , including both ends, use , not . When unsure, check the rule on a list short enough to count by hand; the problem even gave you one such check.
Alternative approach
Count the whole list first: from to there are numbers. Going forward, numbers come before , so going backward, the numbers after are those . The numbers before and including in the backward count are .
Concise solution
A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.
Counting backwards from , the numbers said before reaching are , and then itself. The position of is the number of integers from to inclusive:
The answer is .
Review in the AoPS books
- Introduction to Number Theory, Chapter 1: Integers: The Basics
- Introduction to Counting & Probability, Chapter 1: Counting Is Arithmetic
- Introduction to Algebra, Chapter 20: Special Functions (§20.3)
- Introduction to Counting & Probability, Chapter 2: Basic Counting Techniques
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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.