AMC 10 Step by Step

2013 AMC 10B Problem 4

P1-10~2 minPrint

When counting from 33 to 201201 , 5353 is the 51st51^\mathrm{st} number counted. When counting backwards from 201201 to 33 , 5353 is the nthn^\mathrm{th} number counted. What is nn ?

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Key insight

Counting down from 201 to 53 counts both end numbers, so the count is 201 minus 53, plus 1.

Solution

1. First see the rule on a tiny example. Count down from 1010 to 77: you say 10,9,8,710, 9, 8, 7. That is 44 numbers, but 10−7=310 - 7 = 3. You need one more than the difference, because both ends get said.
2. Test the rule on the fact given in the problem. Counting up from 33, the number 5353 is said 53−3+1=5153 - 3 + 1 = 51st. That matches.
3. Now count down from 201201. The numbers said, up to and including 5353, are 201,200,199,…,54,53201, 200, 199, \ldots, 54, 53. How many is that?
201−53+1=149.201 - 53 + 1 = 149.
So 5353 is the 149149th number said.

The answer is (D) 149\boxed{\textbf{(D)}\ 149}.

Why this works

To count the whole numbers from aa to bb, including both ends, use b−a+1b - a + 1, not b−ab - a. When unsure, check the rule on a list short enough to count by hand; the problem even gave you one such check.

Alternative approach

Count the whole list first: from 33 to 201201 there are 201−3+1=199201 - 3 + 1 = 199 numbers. Going forward, 5050 numbers come before 5353, so going backward, the numbers after 5353 are those 5050. The numbers before and including 5353 in the backward count are 199−50=149199 - 50 = 149.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Counting backwards from 201201, the numbers said before reaching 5353 are 201,200,…,54201, 200, \dots, 54, and then 5353 itself. The position of 5353 is the number of integers from 5353 to 201201 inclusive:
201−53+1=149.201 - 53 + 1 = 149.

The answer is (D) 149\boxed{\textbf{(D)}\ 149}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.