AMC 10 Step by Step

2012 AMC 10B Problem 6

P1-10~1 minPrint

In order to estimate the value of x−yx-y where xx and yy are real numbers with x>y>0x > y > 0 , Xiaoxi rounded xx up by a small amount, rounded yy down by the same amount, and then subtracted her rounded values. Which of the following statements is necessarily correct?

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Key insight

Making the first number bigger and the subtracted number smaller both make the difference bigger. The two roundings add up instead of cancelling.

Solution

1. Try real numbers first. Say x=5x = 5 and y=3y = 3, so the true value of x−yx - y is 22.
2. Round xx up by 0.10.1 to get 5.15.1. Round yy down by 0.10.1 to get 2.92.9.
3. Her estimate is 5.1−2.9=2.25.1 - 2.9 = 2.2. That is bigger than 22 by 0.20.2.
4. Now see why this always happens. Call the rounding amount ee (a small positive number). She uses x+ex + e and y−ey - e, so her estimate is
(x+e)−(y−e)=x+e−y+e=x−y+2e.(x + e) - (y - e) = x + e - y + e = x - y + 2e.
5. Since ee is positive, 2e2e is positive, so the estimate is always bigger than x−yx - y, no matter what xx and yy are.

The answer is (A) Her estimate is larger than x−y\boxed{\textbf{(A)}\ \text{Her estimate is larger than } x-y}.

Why this works

A difference gets bigger when the first number grows, and it also gets bigger when the number being subtracted shrinks. Here both changes push the same way, so their effects add instead of cancelling. When a word problem talks about rounding, write the rounded numbers as "number plus a little" or "number minus a little" and simplify.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Let e>0e > 0 be the small amount used for rounding. Xiaoxi replaces xx by x+ex + e and yy by y−ey - e, so her estimate is
(x+e)−(y−e)=x−y+2e.(x + e) - (y - e) = x - y + 2e.
Since e>0e > 0, this exceeds x−yx - y by the positive amount 2e2e, regardless of the actual values of xx and yy.

The answer is (A) Her estimate is larger than x−y\boxed{\textbf{(A)}\ \text{Her estimate is larger than } x-y}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.