AMC 10 Step by Step

2011 AMC 10A Problem 6

P1-10~1 minPrint

Set AA has 20 elements, and set BB has 15 elements. What is the smallest possible number of elements in A∪BA \cup B , the union of AA and BB ?

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Key insight

The union always contains all 20 elements of A. It has exactly 20 when every element of B is already in A.

Solution

The union A∪BA \cup B is everything that is in AA, in BB, or in both. We want it as small as possible, so we want AA and BB to share as much as they can.

  1. It can't be smaller than 20. The union contains every element of AA, and AA has 2020 elements. So the union has at least 2020.
  2. 20 can happen. Make every element of BB also an element of AA. For example, let AA be the numbers 11 to 2020 and BB be the numbers 11 to 1515. Then the union is just 11 to 2020, which has 2020 elements.

The smallest possible union has 2020 elements.

The answer is (C) 20\boxed{\textbf{(C)}\ 20}.

Why this works

The number of elements in the union is 20+1520 + 15 minus the number of elements the two sets share (otherwise the shared ones are counted twice). The two sets can share at most 1515 elements, since BB only has 1515. Sharing all 1515 gives the smallest union, 2020. Sharing none gives the largest, 3535. Questions about the smallest or largest union usually come down to these two extreme pictures: one set inside the other, or no overlap at all.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

The union contains all of AA, so it has at least 2020 elements.

Exactly 2020 is achievable: let BB consist of 1515 of the elements of AA. Then A∪B=AA \cup B = A, which has 2020 elements.

The answer is (C) 20\boxed{\textbf{(C)}\ 20}.

Review in the AoPS books

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