Bricklayer Brenda would take nine hours to build a chimney alone, and Bricklayer Brandon would take hours to build it alone. When they work together, they talk a lot, and their combined output decreases by bricks per hour. Working together, they build the chimney in hours. How many bricks are in the chimney?
- A)
- B)
- C)
- D)
- E)
Answer
B
Key insight
Measure speed in bricks per hour. Brenda lays one ninth of the chimney each hour and Brandon one tenth; together, minus 10 bricks, they must lay one fifth.
Solution
The slowdown is given in bricks per hour, so measure everyone's speed in bricks per hour too. Call the number of bricks in the chimney .
1. Brenda builds the whole chimney in hours, so she lays bricks each hour.
2. Brandon builds it in hours, so he lays bricks each hour.
3. Together they would lay each hour, but talking costs bricks per hour. Their real speed is .
4. They finish in hours, so their real speed is also bricks per hour:
5. Clear the fractions by multiplying every term by :
6. Subtract from both sides: , so .
7. Check: Brenda lays per hour, Brandon , together per hour, and .
The answer is .
Why this works
Work problems turn into simple equations once everything is written as a speed ("how much per hour"). Speeds of people working together add. Because the slowdown is counted in bricks per hour, the speeds must also be in bricks per hour, which is why the unknown number of bricks shows up in every speed.
Alternative approach
Test the choices, starting with (B). With bricks, Brenda lays per hour and Brandon . Together that is per hour, and hours. It fits. (With bricks, for example, the speeds are and , together per hour, and bricks take less than hours.)
The trap
Taking 10 bricks away from the whole chimney instead of from each hour's work.
Concise solution
Let the chimney contain bricks. Brenda lays bricks per hour and Brandon lays bricks per hour. Together, after the -brick-per-hour loss, their rate is . Finishing in hours means this rate equals :
Multiply through by :
Check: bricks per hour, and .
The answer is .
Review in the AoPS books
- Introduction to Algebra, Chapter 3: One-Variable Linear Equations (§3.3, §3.4)
- Introduction to Algebra, Chapter 7: Proportion (§7.4)
Techniques
Set up the equation/formula and compute; no special trick needed