AMC 10 Step by Step

2007 AMC 10B Problem 1

P1-10~2 minPrint

Isabella's house has 33 bedrooms. Each bedroom is 1212 feet long, 1010 feet wide, and 88 feet high. Isabella must paint the walls of all the bedrooms. Doorways and windows, which will not be painted, occupy 6060 square feet in each bedroom. How many square feet of walls must be painted?

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Key insight

The four walls unfold into one strip 44 feet long and 8 feet tall. Take away the doors and windows, then multiply by three rooms.

Solution

Only the walls get paint. The floor and ceiling do not, so leave them out.

1. Picture walking once around one bedroom. You pass a 1212-foot wall, a 1010-foot wall, another 1212-foot wall and another 1010-foot wall. That is 12+10+12+10=4412 + 10 + 12 + 10 = 44 feet of wall.
2. If you could unfold the four walls and lay them side by side, they would make one long rectangle, 4444 feet long and 88 feet tall. Its area is
44×8=352 square feet.44 \times 8 = 352 \text{ square feet}.
3. The doors and windows in that room are not painted, so take away their 6060 square feet:
352−60=292 square feet.352 - 60 = 292 \text{ square feet}.
4. There are 33 bedrooms that are all the same, so multiply:
3×292=876 square feet.3 \times 292 = 876 \text{ square feet}.

The answer is (E) 876\boxed{\textbf{(E)}\ 876}.

Why this works

The walls of a box-shaped room, laid out flat, make one rectangle whose length is the distance around the floor. That saves adding four separate wall areas. Before you compute, read closely which surfaces count, and handle one room completely before multiplying by the number of rooms.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Only the four walls of each room are painted, not the floor or ceiling. Unrolled, the four walls form one long rectangle whose width is the perimeter of the floor and whose height is 88 feet:
perimeter=2(12+10)=44,wall area=44⋅8=352.\text{perimeter} = 2(12 + 10) = 44, \qquad \text{wall area} = 44 \cdot 8 = 352.

Remove the doors and windows: 352−60=292352 - 60 = 292 square feet per bedroom.

Three bedrooms: 3⋅292=8763 \cdot 292 = 876.

The answer is (E) 876\boxed{\textbf{(E)}\ 876}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site. Also appeared as 2007 12B #1.