AMC 10 Step by Step
2002 AMC 10AProblem 9P1-10~2 minPrint

There are 3 numbers A, B, and C, such that 1001C2002A=40041001C - 2002A = 4004 , and 1001B+3003A=50051001B + 3003A = 5005 . What is the average of A, B, and C?

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.