AMC 10 Step by Step
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Linear Equations & Word Problems

Linear equations/inequalities, word problems, rates, work, mixtures, distance-speed-time

What you need to know

  • A linear equation in one unknown has exactly one solution, unless the xx terms cancel. Then you get something always true, as when 2(x+1)=2x+22(x+1)=2x+2 becomes 0=00=0 (every number works), or never true, as when 2x+1=2x+32x+1=2x+3 becomes 0=20=2 (no number works). Example: 3x+7=223x+7=22 has the one solution x=5x=5.
  • Distance == rate ×\times time, and work done == rate ×\times time. Finishing a job alone in tt hours means a rate of 1t\frac1t of the job per hour. When workers or pipes work together, their rates add. Example: pipes that fill a tank in 44 and 1212 hours together fill 14+112=13\frac14+\frac1{12}=\frac13 of it per hour, so they take 33 hours.
  • Average speed is total distance divided by total time, never the average of the speeds. Example: drive 3030 miles at 3030 mph (11 hour) and back at 1515 mph (22 hours). That is 6060 miles in 33 hours, or 2020 mph, not 22.522.5.
  • Mixtures. The amount of the pure substance stays the same when you mix. If V1V_1 liters at concentration c1c_1 and V2V_2 liters at c2c_2 make a mix at concentration cc, then c1V1+c2V2=c(V1+V2)c_1V_1+c_2V_2=c(V_1+V_2). Example: 22 liters of 10%10\% acid and 33 liters of 20%20\% acid hold 0.2+0.6=0.80.2+0.6=0.8 liters of acid in 55 liters, so the mix is 16%16\% acid.
  • Ages. The difference between two people's ages never changes. Example: Ann is 88 years older than Ben, so she is twice his age when Ben is 88 and she is 1616.

How AMC 10 tests it

  • Problems 1–8: a short word problem (ages, coins, a trip in two parts) that becomes one equation like ax+b=cax+b=c.
  • Problems 5–12: work or pipe problems where the key idea is to add rates, not times.
  • Round-trip speed problems where the average of the two speeds is one of the wrong answer choices.
  • Problems asking for something other than the natural unknown: x+yx+y, the other person's age, a percent.

Standard approaches

  1. Give a letter to the unknown you are asked for, and turn each sentence into one equation.
  2. Turn everything into a rate per unit of time. For trips, call the distance 11 or a handy common multiple.
  3. Pick a friendly total to avoid fractions: the least common multiple of the times, or 100100 for percents. Example: if Al does a job in 44 hours and Bo in 66, call the job 1212 units. Their rates are 33 and 22 units per hour, so together the job takes 125\frac{12}5 hours.
  4. If the equation gets messy, test the answer choices against the story.

Worked example

A pump fills an empty tank in 66 hours, and a drain empties a full tank in 1212 hours. The tank starts empty with the pump running and the drain closed. After tt hours the drain is opened, and the tank becomes exactly full 55 hours after that. What is tt?

(A) 33 (B) 103\frac{10}{3} (C) 72\frac{7}{2} (D) 44 (E) 92\frac{9}{2}

Call a full tank 11. The pump adds 16\frac16 of a tank per hour and the drain removes 112\frac1{12}. With both open, the tank gains 16−112=212−112=112\frac16-\frac1{12}=\frac2{12}-\frac1{12}=\frac1{12} of a tank per hour.

During the first tt hours only the pump runs, so it adds t6\frac t6. During the next 55 hours both are open, adding 5⋅112=5125\cdot\frac1{12}=\frac5{12}. Together these make one full tank:
t6+512=1⟹t6=712⟹t=4212=72. \frac t6+\frac5{12}=1\quad\Longrightarrow\quad \frac t6=\frac7{12}\quad\Longrightarrow\quad t=\frac{42}{12}=\frac72 .
Check: in 72\frac72 hours the pump fills 712\frac7{12}, and 712+512=1\frac7{12}+\frac5{12}=1.

The answer is (C) 72\boxed{\textbf{(C)}\ \frac72}.

Pitfalls

  • Averaging the two speeds instead of dividing total distance by total time.
  • Adding times instead of rates. Example: if one person takes 33 hours alone and another takes 44, together they take 127\frac{12}7 hours, not 77, which is longer than either one alone.
  • Solving for xx but answering a different quantity from the one asked.
  • Forgetting a unit conversion, such as minutes to hours. Example: 2020 minutes is 13\frac13 hour, not 0.20.2 hour.

Traps that recur

  • Assuming that once Michael catches the truck he stays ahead, or missing the two meetings where the gap only touches zero at the end of a stop or a drive. (2008 AMC 10B #25)
  • Forgetting to subtract the lunch break from every day's working time, or converting 2:12 PM and 7:12 PM to hours incorrectly (372 and 672 minutes after 8:00). (2012 AMC 10A #19)
  • Comparing the second mean to the original mean instead of to the enlarged list's mean (it should be m + 2 - 1 = m + 1 with n + 2 numbers). (2002 AMC 10B #25)
  • Writing c + m = 8p and m/4 + c/6 = 8, then stalling with two equations in three unknowns instead of using that c and m are positive. (2000 AMC 10 #22)

Problems © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. The topic note, tags and key insights are original to this site.

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