AMC 10 Step by Step
Printable problems

Exponents, Logarithms & Radicals

Exponent rules, radicals, nested radicals, rationalizing, logarithms (rare)

What you need to know

  • Exponent rules. aman=am+na^ma^n=a^{m+n}, (am)n=amn(a^m)^n=a^{mn} (with fraction exponents this needs a>0a>0: ((−3)2)1/2=3\left((-3)^2\right)^{1/2}=3, not −3-3), a−n=1ana^{-n}=\dfrac1{a^n}, a1/n=ana^{1/n}=\sqrt[n]a, and a0=1a^0=1 (for a≠0a\ne0). Example: 23⋅24=27=1282^3\cdot2^4=2^7=128 and 9−1/2=139^{-1/2}=\frac13.
  • Use a common base. Powers with different bases combine only after you rewrite them with the same base. Example: 4x=22x4^x=2^{2x}, and 9x=279^x=27 becomes 32x=333^{2x}=3^3, so x=32x=\frac32.
  • Square roots. ab=ab\sqrt a\sqrt b=\sqrt{ab} when aa and bb are zero or positive. Also a2=∣a∣\sqrt{a^2}=|a|, not aa. Example: (−5)2=25=5\sqrt{(-5)^2}=\sqrt{25}=5.
  • Rationalizing. To clear the roots from the bottom of 1a±b\dfrac1{\sqrt a\pm\sqrt b}, multiply top and bottom by the conjugate a∓b\sqrt a\mp\sqrt b (same terms, opposite sign). Example: 13+2=3−23−2=3−2\dfrac1{\sqrt3+\sqrt2}=\dfrac{\sqrt3-\sqrt2}{3-2}=\sqrt3-\sqrt2.
  • Denesting. a+2b=m+n\sqrt{a+2\sqrt b}=\sqrt m+\sqrt n and a−2b=m−n\sqrt{a-2\sqrt b}=\sqrt m-\sqrt n, where m+n=am+n=a, mn=bmn=b, and m≥nm\ge n. Check by squaring. Example: (3±2)2=5±26(\sqrt3\pm\sqrt2)^2=5\pm2\sqrt6, so 5±26=3±2\sqrt{5\pm2\sqrt6}=\sqrt3\pm\sqrt2.
  • Logarithms (rare). log⁡bx=y\log_b x=y means the same as by=xb^y=x. For positive xx and yy: log⁡(xy)=log⁡x+log⁡y\log(xy)=\log x+\log y, log⁡xk=klog⁡x\log x^k=k\log x, and log⁡bx=log⁡xlog⁡b\log_b x=\dfrac{\log x}{\log b} (top and bottom in the same base). Example: log⁡28=3\log_2 8=3 because 23=82^3=8, and log⁡48=log⁡28log⁡24=32\log_4 8=\dfrac{\log_2 8}{\log_2 4}=\dfrac32.
  • Comparing huge powers. Take the same root of both. Example: to compare 23002^{300} and 32003^{200}, write them as 81008^{100} and 91009^{100}. So 32003^{200} is bigger.
  • Whole-number roots. For a positive integer NN, Nn\sqrt[n]{N} is an integer exactly when NN is a perfect nnth power. Factor NN to check: every exponent must be a multiple of nn. Example: 216=23⋅33216=2^3\cdot3^3, so 2163=6\sqrt[3]{216}=6; but 72=23⋅3272=2^3\cdot3^2, so 723\sqrt[3]{72} is not an integer.

How AMC 10 tests it

  • Problems 1–8: simplify 22020+2202222021\dfrac{2^{2020}+2^{2022}}{2^{2021}} or find 82/38^{2/3} or (2)6(\sqrt2)^6. The trick is factoring out the smallest power.
  • Problems 5–12: solve 2x+1=8x−22^{x+1}=8^{x-2} (match the bases) or x+5−x=1\sqrt{x+5}-\sqrt x=1 (get a root alone, square, check).
  • Problems 8–15: "which is largest" among 240,330,5202^{40},3^{30},5^{20}, or the number of digits of 2k5m2^{k}5^{m}.
  • Problems 10–18: nested roots like 6+6+⋯\sqrt{6+\sqrt{6+\cdots}}, or sums of 1k+k+1\frac1{\sqrt k+\sqrt{k+1}} that you rationalize and then telescope (almost everything cancels).
  • Logarithms show up only now and then, usually late in the paper, as an exponent equation in disguise.

Standard approaches

  1. Write everything with one base and set the exponents equal. Example: 8x−2=23x−68^{x-2}=2^{3x-6}, so 2x+1=8x−22^{x+1}=8^{x-2} means x+1=3x−6x+1=3x-6, and x=72x=\frac72.
  2. In a sum of powers, factor out the smallest power: 2n+2n+2=2n(1+4)2^n+2^{n+2}=2^n(1+4). Example: 22020+2202222021=22020⋅522021=52\dfrac{2^{2020}+2^{2022}}{2^{2021}}=\dfrac{2^{2020}\cdot5}{2^{2021}}=\dfrac52.
  3. For an equation with square roots, get one root alone, square, repeat if needed, and test every answer in the original equation. Example: x+5=1+x\sqrt{x+5}=1+\sqrt x squares to x+5=1+2x+xx+5=1+2\sqrt x+x, so x=2\sqrt x=2 and x=4x=4. Check: 3−2=13-2=1.
  4. For nested or never-ending roots, either guess a denested form m±n\sqrt m\pm\sqrt n, or set xx equal to the whole expression and square. Example: if x=6+6+⋯x=\sqrt{6+\sqrt{6+\cdots}}, then x2=6+xx^2=6+x, so x=3x=3 (the other root, −2-2, is negative).
  5. To compare sizes, take a common power or root, or compare logarithms. Example: the 1010th roots of 240,330,5202^{40},3^{30},5^{20} are 16,27,2516,27,25, so 3303^{30} is largest.

Worked example

Let xx be a real number with 4x+4−x=344^x+4^{-x}=34. What is 8x+8−x8^x+8^{-x}?

(A) 102102 (B) 162162 (C) 198198 (D) 204204 (E) 216216

Let t=2x+2−xt=2^x+2^{-x}. Both terms are positive, so tt is positive. Squaring uses (2x)2=4x(2^x)^2=4^x and 2x⋅2−x=12^x\cdot2^{-x}=1:
t2=4x+2+4−x=34+2=36,t=6. t^2=4^x+2+4^{-x}=34+2=36,\qquad t=6 .
Now cube. Let u=2xu=2^x and v=2−xv=2^{-x}, so u+v=6u+v=6 and uv=1uv=1. Since 8x=(2x)3=u38^x=(2^x)^3=u^3 and 8−x=v38^{-x}=v^3, we want u3+v3u^3+v^3. The identity u3+v3=(u+v)3−3uv(u+v)u^3+v^3=(u+v)^3-3uv(u+v) gives
8x+8−x=t3−3t=216−18=198. 8^x+8^{-x}=t^3-3t=216-18=198 .
The answer is (C) 198\boxed{\textbf{(C)}\ 198}.

Pitfalls

  • Writing a+b=a+b\sqrt{a+b}=\sqrt a+\sqrt b or (a+b)2=a2+b2(a+b)^2=a^2+b^2. Example: 9+16=5\sqrt{9+16}=5, not 3+4=73+4=7.
  • Adding exponents across different bases. Example: 23⋅32=722^3\cdot3^2=72, not 656^5.
  • Keeping an extra root that appeared when you squared. Example: squaring x=x−2\sqrt x=x-2 gives x=(x−2)2x=(x-2)^2, so x=1x=1 or x=4x=4. But x=1x=1 gives 1=−11=-1, so only x=4x=4 works.
  • Forgetting x2=∣x∣\sqrt{x^2}=|x|, which loses a negative solution or causes a sign error. Example: x2=3\sqrt{x^2}=3 has two solutions, x=3x=3 and x=−3x=-3.

Traps that recur

  • Counting 2014 powers of 2 (including 2^0 or 2^2014) instead of 2^1 through 2^2013, which gives 280. (2014 AMC 10A #25)
  • For the fifth root, dividing 312 by 5 and taking the leading digit of the fifth root of 7.77, which ignores that 312 is not a multiple of 5. (2021 AMC Fall 10B #19)
  • Guessing that x and y need not be multiples of 7, or splitting 13 unevenly (like 1 and 12) and reporting a larger sum such as 7 * 145. (2024 AMC 10B #13)
  • Ignoring the 2-power terms and answering 3^4 = 81 exactly, when the fraction is strictly less than 81 because 2^100 = 16 2^96 is much smaller than 81 2^96. (2018 AMC 10A #14)

Problems © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. The topic note, tags and key insights are original to this site.