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2024 AMC 10B Problem 2

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2024 AMC 10B Problem 2AMC 10 Step by Step
Name:                             Date: September 13, 2026
Algebraic Manipulation · difficulty 1 of 5 · about 1 min · position P1-10

What is 10!−7!⋅6!10! - 7! \cdot 6!

(A) −120(B) 0(C) 120(D) 600(E) 720\textbf{(A) } -120 \qquad\textbf{(B) } 0 \qquad\textbf{(C) } 120 \qquad\textbf{(D) } 600 \qquad\textbf{(E) } 720

[ONLY FOR CERTAIN CHINESE TESTPAPERS]

What is 10!−7!⋅6!−5!10! - 7! \cdot 6! - 5!

  1. A)

    −120-120

  2. B)

    00

  3. C)

    120120

  4. D)

    600600

  5. E)

    720720

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