2021 AMC 10B Problem 5
The ages of Jonie's four cousins are distinct single-digit positive integers. Two of the cousins' ages multiplied together give , while the other two multiply to . What is the sum of the ages of Jonie's four cousins?
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Key insight
Using single digits, 30 can only be 5 × 6. Since 6 is now taken, 24 has to be 3 × 8, not 4 × 6.
Solution
Each product is made from two different ages, each from to . List the ways to make each product.
- Start with 30, since it has fewer choices:
Only uses two single digits. So two cousins are and .
- Now 24:
The single-digit options are and . But is already one cousin's age, and all four ages are different. So the other two cousins are and .
- Add all four ages: .
The answer is .
Why this works
Start with the part that has the fewest possibilities. The single-digit rule leaves only one choice, and then "all ages different" leaves only one choice too. A short list plus one rule is quicker than any algebra.
Concise solution
A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.
Write each product as a pair of distinct single-digit factors.
; only uses single digits. So two cousins are and .
(the pairs and are out). Since is already used and ages are distinct, the other two cousins are and .
Sum: .
The answer is .
Review in the AoPS books
- Introduction to Number Theory, Chapter 1: Integers: The Basics (§1.4, §1.5)
- Prealgebra, Chapter 15: Problem-Solving Strategies (§15.2)
- Introduction to Number Theory, Chapter 5: Divisor Problems (§5.2, §5.3)
- Introduction to Number Theory, Chapter 13: Divisibility Rules (§13.2)
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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.