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2021 AMC 10A Problem 5

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2021 AMC 10A Problem 5AMC 10 Step by Step
Name:                             Date: September 13, 2026
Ratios, Percents & Averages · difficulty 2 of 5 · about 2 min · position P1-10

The quiz scores of a class with k>12k > 12 students have a mean of 88 . The mean of a collection of 1212 of these quiz scores is 1414 . What is the mean of the remaining quiz scores in terms of kk ?

  1. A)

    14−8k−12\frac{14-8}{k-12}

  2. B)

    8k−168k−12\frac{8k-168}{k-12}

  3. C)

    1412−8k\frac{14}{12} - \frac{8}{k}

  4. D)

    14(k−12)k2\frac{14(k-12)}{k^2}

  5. E)

    14(k−12)8k\frac{14(k-12)}{8k}

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