2020 AMC 10B Problem 4
The acute angles of a right triangle are and , where and both and are prime numbers. What is the least possible value of ?
Show solution without answering
Key insight
The two acute angles add to 90. Try b = 2, 3, 5, 7 in order and stop at the first one where 90 minus b is also prime.
Solution
- In a right triangle the three angles add to and one of them is . So the two acute angles add to : .
- We want the smallest prime for which is also prime. Since we want the smallest, start at the smallest prime and go up.
| Is prime? | ||
|---|---|---|
| No, it is even | ||
| No, | ||
| No, | ||
| Yes |
- At we get , which is prime, and as required. No smaller worked.
The answer is .
Why this works
For a "least possible" question with only a few candidates, test them from smallest upward and stop at the first one that works. A quick shortcut: is even, so if then is even too and cannot be prime. That is why the smallest prime fails right away.
Concise solution
A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.
In a right triangle the two acute angles satisfy . We want the smallest prime for which is also prime (and automatically ).
Check primes from the bottom:
- : , even, not prime.
- : , not prime.
- : , not prime.
- : , which is prime.
So the least possible value is .
The answer is .
Review in the AoPS books
- Introduction to Number Theory, Chapter 2: Primes and Composites
- Introduction to Geometry, Chapter 2: Angles
- Prealgebra, Chapter 15: Problem-Solving Strategies (§15.2)
- Introduction to Number Theory, Chapter 4: Prime Factorization (§4.2, §4.4)
Similar problems
Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.