AMC 10 Step by Step

2020 AMC 10B Problem 4

P1-10~2 minPrint

The acute angles of a right triangle are a∘a^{\circ} and b∘b^{\circ} , where a>ba>b and both aa and bb are prime numbers. What is the least possible value of bb ?

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Key insight

The two acute angles add to 90. Try b = 2, 3, 5, 7 in order and stop at the first one where 90 minus b is also prime.

Solution

  1. In a right triangle the three angles add to 180∘180^\circ and one of them is 90∘90^\circ. So the two acute angles add to 90∘90^\circ: a+b=90a + b = 90.
  2. We want the smallest prime bb for which a=90−ba = 90 - b is also prime. Since we want the smallest, start at the smallest prime and go up.
bba=90−ba = 90 - bIs aa prime?
228888No, it is even
338787No, 87=3×2987 = 3 \times 29
558585No, 85=5×1785 = 5 \times 17
778383Yes
  1. At b=7b = 7 we get a=83a = 83, which is prime, and 83>783 > 7 as required. No smaller bb worked.

The answer is (D) 7\boxed{\textbf{(D)}\ 7}.

Why this works

For a "least possible" question with only a few candidates, test them from smallest upward and stop at the first one that works. A quick shortcut: 9090 is even, so if b=2b = 2 then aa is even too and cannot be prime. That is why the smallest prime fails right away.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

In a right triangle the two acute angles satisfy a+b=90a + b = 90. We want the smallest prime bb for which a=90−ba = 90 - b is also prime (and automatically a>ba > b).

Check primes from the bottom:

  • b=2b = 2: a=88a = 88, even, not prime.
  • b=3b = 3: a=87=3⋅29a = 87 = 3 \cdot 29, not prime.
  • b=5b = 5: a=85=5⋅17a = 85 = 5 \cdot 17, not prime.
  • b=7b = 7: a=83a = 83, which is prime.

So the least possible value is b=7b = 7.

The answer is (D) 7\boxed{\textbf{(D)}\ 7}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.