Sangho uploaded a video to a website where viewers can vote that they like or dislike a video. Each video begins with a score of , and the score increases by for each like vote and decreases by for each dislike vote. At one point Sangho saw that his video had a score of , and that of the votes cast on his video were like votes. How many votes had been cast on Sangho's video at that point?
- A)
- B)
- C)
- D)
- E)
Answer
B
Key insight
Out of every 100 votes, 65 are likes and 35 are dislikes, so each 100 votes adds 30 to the score. A score of 90 needs 300 votes.
Solution
Start with a small concrete batch of votes to see how the score grows.
- Look at votes. of them are likes, so likes and dislikes.
- Score from those votes. Each like adds and each dislike takes away , so the score is .
- Scale up. Every votes (in the same to split) adds to the score. The score is , so there must be votes.
- Check. of is likes, leaving dislikes. Score: . Correct.
The answer is .
Why this works
Likes and dislikes are both fixed shares of the same total. Their difference, , is also a fixed share of the total, and that difference is exactly the score. So the score is of all votes, and of is .
Alternative approach
Try the answer choices. With votes: likes and dislikes, score . Too small. With votes: . That matches, and more votes would only raise the score, so is the answer.
The trap
Treating the score as the number of likes, so that 65% of the votes equals 90. Each dislike takes a point away, so only the gap between likes and dislikes counts.
Concise solution
Let be the total number of votes. Likes make up of them and dislikes the remaining , so
The score is likes minus dislikes:
Hence .
Check: likes and dislikes give a score of , and .
The answer is .
Review in the AoPS books
- Introduction to Algebra, Chapter 6: Ratios and Percents
- Introduction to Algebra, Chapter 3: One-Variable Linear Equations (§3.3, §3.4)
- Introduction to Algebra, Chapter 7: Proportion (§7.1, §7.2, §7.3)
- Prealgebra, Chapter 13: Data and Statistics (§13.1)
Techniques
Set up the equation/formula and compute; no special trick needed