AMC 10 Step by Step

2017 AMC 10B Problem 5

P1-10~2 minPrint

Camilla had twice as many blueberry jelly beans as cherry jelly beans. After eating 1010 pieces of each kind, she now has three times as many blueberry jelly beans as cherry jelly beans. How many blueberry jelly beans did she originally have?

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Key insight

Call the cherry count c, so blueberry is 2c. After eating 10 of each, 2c - 10 = 3(c - 10), so c = 20 and blueberry is 40.

Solution

There are fewer cherry jelly beans, so give that number a name and write everything else in terms of it.

1. Let cc be the number of cherry jelly beans at the start. Blueberry is twice as many: 2c2c.
2. After eating 1010 of each, she has c−10c - 10 cherry and 2c−102c - 10 blueberry.
3. Now blueberry is three times cherry:
2c−10=3(c−10)=3c−30.2c - 10 = 3(c - 10) = 3c - 30.
4. Add 3030 to both sides and subtract 2c2c: c=20c = 20.
5. The question asks for blueberry at the start: 2c=402c = 40.
6. Check: at the start 4040 and 2020 (twice as many). After eating, 3030 and 1010 (three times as many).

The answer is (D) 40\boxed{\textbf{(D)}\ 40}.

Why this works

Two "times as many" facts about the same two amounts, one before and one after a change, give one equation with one unknown. Name the smaller amount, write the larger one using the first fact, then use the second fact on the changed amounts. Before answering, re-read which amount the question wants.

Alternative approach

Test the choices as the blueberry count. With 4040 blueberry there were 2020 cherry; after eating 1010 of each there are 3030 and 1010, exactly three times. Checking the others: 5050 blueberry and 2525 cherry leaves 4040 and 1515, not three times; the smaller choices fail the same way.

Concise solution

A shorter write-up, the way contest solutions are usually written. It may take a different route from the solution above.

Let cc be the original number of cherry jelly beans, so there were 2c2c blueberry ones. After eating 1010 of each, the counts are c−10c - 10 and 2c−102c - 10, and the new ratio is 3:13 : 1:
2c−10=3(c−10)=3c−30.2c - 10 = 3(c - 10) = 3c - 30.
So c=20c = 20, and the original blueberry count is 2c=402c = 40. Check: 3030 blueberry and 1010 cherry remain, a 3:13:1 ratio.

The answer is (D) 40\boxed{\textbf{(D)}\ 40}.

Review in the AoPS books

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Problem © Mathematical Association of America (MAA), American Mathematics Competitions. Reproduced for non-commercial educational use. Solution and commentary are original to this site.