Sofia ran laps around the -meter track at her school. For each lap, she ran the first meters at an average speed of meters per second and the remaining meters at an average speed of meters per second. How much time did Sofia take running the laps?
- A)
- B)
- C)
- D)
- E)
Answer
C
Key insight
Time equals distance over speed for each segment: 100/4 = 25 s plus 300/5 = 60 s gives 85 s per lap, times 5 laps.
Solution
Compute the time for one lap segment by segment.
- First meters at m/s: seconds.
- Remaining meters at m/s: seconds.
One lap takes seconds, so five laps take seconds. Since , that is minutes and seconds.
The answer is .
Why this works
Speeds do not add or average directly; times do. Whenever a trip has pieces at different speeds, compute each piece's time with and add. The final unit conversion ( s to min:sec) is where careless errors happen, so do it last and check it.
The trap
Averaging the two speeds to 4.5 m/s and dividing 2000 m by it, which ignores that the segments have different lengths.
Common mistakes
- Averaging the two speeds to 4.5 m/s and dividing 2000 m by it, which ignores that the segments have different lengths.
- Computing seconds per lap correctly but forgetting to multiply by , or misconverting seconds.
Techniques
Set up the equation/formula and compute; no special trick needed